β⁻ emission is an
emission of an electron from the parent atom while converting a neutron into a
proton.<span> Hence, the formed daughter nucleus has the same
number of mass but the atomic number is higher by 1 and number of neutrons is
lower by one than the parent atom.</span><span>
After a β⁻<span> emission of ¹⁰⁶Ru, the formed daughter nucleus
should have 106 as mass number but (44 + 1) = 45 </span>as the atomic number. </span><span>
<span>Hence the daughter nucleus is </span>Rh<span> (</span>Rhodium<span>) which has </span>45<span> protons
(atomic number).</span></span>
Hello.
Active site of the enzyme.
Have a nice day
Incorrect, temperature is directly proportional to the avg. KE of a gas.
Answer:
V CH4(g) = 190.6 L
Explanation:
assuming ideal gas:
∴ STP: T =298 K and P = 1 atm
∴ R = 0.082 atm.L/K.mol
∴ moles (n) = 7.80 mol CH4(g)
∴ Volume CH4(g) = ?
⇒ V = RTn/P
⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)
⇒ V CH4(g) = 190.6 L
Answer:
H₂O is the limiting reactant
Theoretical yield of 240 g Al₂O₃ and 14 g H₂
Explanation:
Find how many moles of one reactant is needed to completely react with the other.
6.5 mol Al × (3 mol H₂O / 2 mol Al) = 9.75 mol H₂O
We need 9.75 mol of H₂O to completely react with 6.5 mol of Al. But we only have 7.2 mol of H₂O. Therefore, H₂O is the limiting reactant.
Now find the theoretical yield:
7.2 mol H₂O × (1 mol Al₂O₃ / 3 mol H₂O) × (102 g Al₂O₃ / mol Al₂O₃) ≈ 240 g Al₂O₃
7.2 mol H₂O × (3 mol H₂ / 3 mol H₂O) × (2 g H₂ / mol H₂) ≈ 14 g H₂
Since the data was given to two significant figures, we must round our answer to two significant figures as well.
