At 45.2 L cylinder containing C2H2F4 at a pressure of 3.00 atm is connected by the valve to 4060 mL cylinder containing N2H4 at

Question

Naily [24]

2 years ago

8

At 45.2 L cylinder containing C2H2F4 at a pressure of 3.00 atm is connected by the valve to 4060 mL cylinder containing N2H4 at

1.50 atm pressure. Calculate the partial pressuure(atm) of N2H4 when the valve is opened.

Chemistry

1 answer:

puteri [66] · Answer 1 · 2023-09-13T02:30:27+03:00

The partial pressure of the N2H4 gas is 1.50 atm.

<h3>Dalton's law of partial pressure</h3>

From the Dalton's law of partial pressure, the total pressure of a mixture of gases is the sum of the individual partial pressures of all the gases present in the mixture.

We have the following;

C2H2F4 = 3.00 atm

N2H4 = c

Total pressure = 3.00 atm + 1.50 atm = 4.50 atm

Hence, the partial pressure of the N2H4 is N2H4.

Learn more about partial pressure: brainly.com/question/14623719