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astraxan [27]
3 years ago
12

A farmhouse shelters 18 animals. Some are cows and some are chickens. Altogether there are 68 legs how many of each animal are t

here?
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

The number of cows in farmhouse shelter is 16

The number of chickens in farmhouse shelter is 2   .

Step-by-step explanation:

Total number of animals in farmhouse shelters = 18

Total number of legs of both animals = 68 legs

Let The number of cows = C

Let The number of chickens = c

∵  the number of legs does each cow has = 4

And, The number of legs does each chicken has = 2

<u>According to question</u>

∵Total number of animals in farmhouse shelters = 18

i.e number of cows + number of chickens = 18

Or, C + c = 18                       .....1

<u>Again</u>

∵ Total number of legs of both animals = 68 legs

i.e  number of cows × number of legs does each cow has + number of chickens × number of legs does each chicken has = 68

Or, C × 4 + c × 2 = 68

i.e 4 C + 2 c = 68                     ........2

Solving eq 1 and eq 2 , we get

(4 C + 2 c ) - 2 × (C + c) = 68 - 2 × 18

Or, (4 C - 2 C) + (2 c - 2 c) = 68 - 36

Or, 2 C + 0 = 32

∴  C = \dfrac{32}{2}

i.e C = 16

So, The number of cows in farmhouse shelter = C = 16

<u>Again</u>

Put the value of C into eq 1

∵ C + c = 18

Or, c = 18 - C

Or, c = 18 - 16

i.e c = 2

So, The number of chickens in farmhouse shelter = c = 2

Hence, The number of cows in farmhouse shelter is 16 and The number of chickens in farmhouse shelter is 2   . Answer

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