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rosijanka [135]
3 years ago
8

How many moles of CO2 are produced when 35.0 mol C2H2 react completely?

Chemistry
1 answer:
GarryVolchara [31]3 years ago
4 0
1) Chemical reaction:


2C2H2 + 5O2 --->   4CO2 + 2H2O


2) Molar ratios


2 mol C2H2 : 5 mol O2 : 4 mol CO2 : 2 mol H2O



3) proportion with 35.0 mol C2H2


2 mol C2H2 / 4 mol CO2 = 35.0 mol C2H2 / x


=> x = 35.0 mol C2H2 * 4 mol CO2 / 2 mol C2H2 = 70.0 mol CO2.


Answer: 70.0 mol CO2
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<u>Answer:</u> The total volume of the gaseous products is 1044.29 L

<u>Explanation:</u>

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = \frac{1}{22.4}\times 116=5.18mol of butane

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

  • <u>For carbon dioxide:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = \frac{8}{2}\times 5.18=20.72mol of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

  • <u>For water vapor:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = \frac{10}{2}\times 5.18=25.9mol of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

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3 H1 NMR signals

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NB: kindly check the diagram of the chemical compound in the attached picture.

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In order to solve this question, one has to count the number of hydrogen in unique location. The diagram in the attached show how hydrogen is been counted.

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<u>Answer:</u> 72 grams of water will be produced.

<u>Explanation:</u>

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ....(1)

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Molar mass of propane = 44 grams

Putting values in above equation, we get:

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By Stoichiometry of the reaction,

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So, 1 mole of propane will produce = \frac{1}{1}\times 4=4moles of water.

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Molar mass of water = 18 g/mol

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Mass of water produced = 72 grams

Hence,  72 grams of water will be produced.

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3 years ago
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