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chubhunter [2.5K]
3 years ago
5

A student pours ammonium nitrate into a container of room temperature water. The student stirs the mixture with a stirring rod a

nd then feels the outside of the container, which is cold to the touch. Which material is part of the system that absorbed heat?
the water

the air

the stirring rod

the container
Chemistry
2 answers:
Vedmedyk [2.9K]3 years ago
8 0

The material which is part of the system that absorbed heat is; The water.

Discussion:

According to the question;

  • Water was initially at room temperature.
  • We know by convention, ammonium nitrate is a cold substance.

In essence, the heat liberated from the system must have been absorbed by the water so that the outside of the container after mixing becomes cold.

This is so because water has a high specific heat capacity.

Read more on heat capacity:

brainly.com/question/16559442

Inga [223]3 years ago
5 0

The material that absorbs the heat of the system is water owing to its high specific heat capacity.

The specific heat capacity of a substance refers to the amount of heat that is capable of increasing the temperature of 1 Kg of a body by 1 K. The higher the specific heat capacity, the more the amount of heat that the body can absorb without temperature change.

The material that absorbs the heat of the system is water because water has a higher specific heat capacity than all the other materials present.

Learn more about specific heat capacity: brainly.com/question/2530523

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3 years ago
What volume of concentrated (10.2 M) HCl would be required to prepare 1.11 x 104 mL of 1.5 M HC1? Enter your answer in scientifi
Tomtit [17]

Answer:

The required volume is 1.6 x 10³mL.

Explanation:

When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:

C₁ . V₁ = C₂ . V₂

where,

C₁ and V₁ are the concentration and volume of the concentrated solution

C₂ and V₂ are the concentration and volume of the dilute solution

In this case, we want to find out V₁:

C₁ . V₁ = C₂ . V₂

V_{1} = \frac{C_{2}.V_{2}}{C_{1}} = \frac{1.5M \times1.11.10^{4}mL }{10.2M} =1.6\times10^{3} mL

3 0
3 years ago
If a sample of hydrochloric acid is neutralized with sodium hydroxide, what products are formed?
GenaCL600 [577]
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6 0
3 years ago
if you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
OverLord2011 [107]

Answer:

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STEP 4: analyze your results

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7 0
3 years ago
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