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Pie
3 years ago
12

The change of matter from a gas state to a liquid state

Chemistry
1 answer:
lara [203]3 years ago
5 0
Condensation ..when gas cool down into liquid statr its called condensation..
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Pavlova-9 [17]

Answer: did you ever find the answer? I need part E, F, and G if you found them please!!!!! I’m begging, my school year ends in 30 minutes and I gotta get this submitted!!!!!!

Explanation:

7 0
2 years ago
Unknown element x has four energy levels, five valence electrons, and is a metalloid. what is elements x?
kykrilka [37]

Answer:

Element X is Arsenic (As)

Explanation:

  • Elements in the periodic table are either metals, non-metals or metalloids.
  • Metals are elements that react by losing electrons to obtain a stable configuration and form cation.
  • Non-metals are those elements that react by gaining electrons to form a stable configuration and form anion.
  • Metalloids are elements in the periodic table that have both metallic and non-metallic properties.
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8 0
3 years ago
When a seed germinates a new plant begins to grow. What is another word for germinates
olga_2 [115]

Answer:

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Explanation:

Any of them.

7 0
2 years ago
What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
3 years ago
Help me out please!?
Sholpan [36]

Answer:

area a

Explanation:

6 0
3 years ago
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