Answer: Choice C)
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mean = xbar = (2400+1750+1900+2500+2250+2100)/6
mean = 2150
Subtract the data values from the mean to get
2400-2150 = 250
1750-2150 = -400
1900-2150 = -250
2500-2150 = 350
2250-2150 = 100
2100-2150 = -50
The differences are: 250, -400, -250, 350, 100, -50
Then you square those values and add up the squares
(250)^2 + (-400)^2 + (-250)^2 + (350)^2 + (100)^2 + (-50)^2 = 420,000
I don't understand the question
Draw a right triangle to represent the problem.
The vertical height of the triangle is 9 ft, and it represents the tree.
The horizontal length, at the bottom of the tree is ground level and has a length of 13 ft.
Let x = angle of elevation.
By definition,
tan x = 9/13 = 0.6923
x = arctan(0.6923) = 34.7 deg. = 35 deg (approx)
Answer: 35°
Answer:
0.84
Step-by-step explanation:
Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:
P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95
We are to find out P(A'UB)
We have
![P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84](https://tex.z-dn.net/?f=P%28A%27UB%29%20%3D%20P%28A%27%29%2BP%28B%29-P%28A%27%20%5Cbigcap%20B%29%5C%5C%3D%201-P%28A%29%20%2BP%28B%29-%5BP%28B%29-P%28A%20%5Cbigcap%20B%29%5D%5C%5C%3D%201-0.86%2B0.79-P%28B%29%2B%5Btex%5DP%28A%27UB%29%3D0.14%2B0.79-0.79%2B0.70%5C%5C%3D0.84)
P(A \bigcap B)[/tex]
