(-2x + 4y)(3x - 7y) = -6x^2 - 28y^2 + 12yx
Hey there! I was looking at your question for a bit then realized you meant 
, the imaginary number, not "1" at the end of each number.
- Complex numbers are numbers involving both real and imaginary numbers; thus, this question wouldn't make much sense without the imaginary number
The expression we are given is:
Open parenthesis and combine like terms:
This is answer choice B (assuming it's supposed to be an and not a "1" at the end)
Let me know if you need any clarifications, thanks!
~ Padoru
2
Hope I helped!
Let me know if you need anything else!
<span>~ Zoe (Rank:'Genius')</span>
<span>-2x^2-x+7=0
Variable with the highest degree's (exponent) constant, -2 is a, next variable's constant, -1 is b, the constant or number without a variable, 7 is c
using substitution put the numbers into the formula
</span>(-b±√(b^(2)-4ac))/(a^(2))
(-(-1)±√((-1)^(2)-4(-2)(7))/((-2)^(2)) simplify
(1±√(1+56))/4
1±√(57)/4 is your answer
Answer:
Need more info
Step-by-step explanation:
