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3 years ago

Graph: y =

Mathematics

1 answer:

Snezhnost [94]3 years ago

7 0

Answer:

Here it is. I recommend using desmos graphing calculator online! :)

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What would be this answer for the algebra thing

skad [1K]

Answer:

c. 4x + 20 = 140

Step-by-step explanation:

Perimeter = 140 feet

Width = L + 10

P = 2w + 2L

P = 2(L + 10) + 2L

P = 2L + 20 + 2L

P = 4L + 20

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2 years ago

Draw a quadrilateral that does not belong, then explain why. What should I draw and write?

Anna007 [38]

Answer

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Step-by-step explanation:

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3 years ago

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Given a triangle has side lengths of 4 inches and 6 inches, which of the following could be a length of the third side? (Check a

Solnce55 [7]

10 inches your hypotenuse is always going to be equal or bigger than the sum of the two sides

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3 years ago

Can someone help me with this?? If you can't see the picture don't bother to answer.

Georgia [21]

J is correct. the scale is balanced, so x = 1. there are 9 1’s on the right, and 6 1’s on the left. there are 3 more blocks, and they would have to each be 1.

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3 years ago

Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective

soldier1979 [14.2K]

Answer:

a) $P[C]=p^n$

b) $P[M]=p^{8n}(9-8p^n)$

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

$P[C]=p^n$

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

$P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)$

$P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9$

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

$P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2$

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0

4 years ago