Hello!
<u><em>Answer: ⇒⇒⇒⇒⇒⇒⇒ =54</em></u>
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Step-by-step explanation:
First you had to convert element to fraction.
Then you had to cross out by the common factor of 3.
Multiply by the fraction.
Multiply by the number.
Again multiply by the number.
Apply rule.
54 is the right answer.
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Hope this helps!
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Have a great day!
-Charlie
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Answer:
Wednesday is 45 to 18.
Thursday is 55 to 22
Step-by-step explanation:
Wednesday: The original ratio was 5 to 2 And the info tells us that the new ratio is ? to 18. To find the first part we have to find how we got from 2 to 18. 2 * 9 = 18. So to find out the first part you do 5 * 9 = 45. We multiply 5 because Thats the original 1st part. We multiply 9 because that's how we got to 18 in the 2nd part. So the answer is 45 for Wednesday.
Thursday: The original ratio was 5 to 2 And the info tells us that the new ratio is 55 to ?. To find the first part we have to find how we got from 5 to 55. 5 * 11 = 55. So to find out the 2nd part you do 2 * 11 = 55. We multiply 2 because That's the original 2nd part. We multiply 11 because that's how we got to 55 in the 1st part. So the answer is 22 for Thursday.
I needed help with that too
Since the sum of the probabilities of all possible outcomes must be 100%, we can deduce the following:
- Cooking in under 20 minutes: 10%
- Cooking between 20 and 30 minutes: 85%
- Cooking in more than 30 minutes: 5%
In fact, the probabilities of cooking in less than 20 or more than 30 sum up to 15%, which means that the remaining outcome (i.e. cooking time between 20 and 30) must complete this probability to 15, and in fact 15+85=100.
That being said, all three answers are simply a combination of these three scenarios: let C be the cooking time, for aesthetic reasons:
Answer:
Step-by-step explanation:
My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.
