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3 years ago

I need helpppp pleasee

Mathematics

1 answer:

zzz [600]3 years ago

3 0

The problem is -2a - 5 > 3
we have - 2a>3+5
or - 2a>8 and now we divide by - 2
and a< 8/(-2) or a< -4
That means you have to choose D- the last line

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Does anyone know what 1+1 is?

hammer [34]

1+1 = 2 that is the answer

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2 years ago

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In the decimal 55.555, which is 1/10 the value of the 5 in the tenths place?

inna [77]

Answer:

55.555

Step-by-step explanation:

1/10 × 1/10 = 1/100

The value in the hundredths place is 1/10 the value in the tenths place.

55.555

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2 years ago

Solve the equation for v<br> <img src="https://tex.z-dn.net/?f=y%3D%5Cfrac%7B8%7D%7Bav%7D%20%2B7" id="TexFormula1" title="y=\fra

My name is Ann [436]

Answer:

$v = \dfrac{8}{a(y - 7)}$

Step-by-step explanation:

$y = \dfrac{8}{av} + 7$

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Multiply both sides by v.

$v(y - 7) = \dfrac{8}{a}$

Multiply both sides by 1/(y - 7).

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3 0

3 years ago

An urn contains 8 pink and 5 red balls. Six balls arerandomly drawn from the urn in succession, with replacement.That is, after

slega [8]

0.088

Step-by-step explanation:

The total number of balls in the urn is;

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To get the probability that all 6 balls drawn from the urn are pink, we will use the AND probability rule of the mutually exclusive events which means we’ll multiply the probabilities of each of the six pink balls;

8/12 * 8/12 * 8/12 * 8/12 * 8/12 * 8/12

= 0.088

Learn More:

For more on probabilities check out;

brainly.com/question/11248705

brainly.com/question/1177537

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3 years ago

Which equation(s) have x = –3 as the solution? log3(2x + 15) = 2 log5(8x + 9) = 2 log4(–20x + 4) = 3 logx81 = 4

baherus [9]

Answer:

log_3(2x+15)=2 and log_4(-20x+4)=3

Step-by-step explanation:

Plug it in and see!

$log_3(2x+15)=2\\log_3(2(-3)+15)=2\\log_3(-6+15)=2\\log_3(9)=2\\\text{ This is a true equation because } 3^2=9\\\\\\log_5(8(-3)+9)=2\\log_5(-24+9)=2\\log_5(-15)=2\\\\\text{ Not true because you cannot do log of a negative number }\\\\log_4(-20(-3)+4)=3\\log_4(64)=3\\\text{ this is true because } 4^3=64\\\\\\log_x (81)=4\\log_{-3}(81)=4\\\text{ the base cannot be negative }\\\\\\\\\text{ There is only two options here} \\\\log_3(2x+15)=2 \text{ and } log_4(-20x+4)=3$

6 0

3 years ago

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