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Bad White [126]
3 years ago
11

How does air resistance affect forward motion

Physics
2 answers:
lord [1]3 years ago
8 0

It creates friction on the forward moving object, causing it to loose momentum, until finally, it stops.

Hope this helps!

Pie3 years ago
4 0
Because the air is resisting the car or something to move
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A 5 μF capacitor is connected to a 12 V battery. The charge on each plate of the capacitor is:
ziro4ka [17]
1 farad = 1 coulomb/volt

5 μF = 5 x 10⁻⁶ coulomb/volt

        = 60 x 10⁻⁶ coulomb / 12 volts

The charge is 60 x 10⁻⁶ coulombs = 6 x 10⁻⁵  (choice-A) 


3 0
3 years ago
Một vật được ném xiên lên từ đỉnh của một tòa nhà cao 20m với góc 600 so với phương ngang, tốc độ ban đầu là 10m/s. Xác định độ
const2013 [10]

Answer:

Một vật được ném xiên lên từ đỉnh của một tòa nhà cao 20m với góc 600 so với phương ngang, tốc độ ban đầu là 10m/s. Xác định độ cao cực đại của vật so với mặt đất?

Explanation:

7 0
2 years ago
A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red
Colt1911 [192]

Answer:

6.59\times 10^7m/s

Explanation:

We are given that

Wavelength of red light=\lambda=635nm

Wavelength of  green light=\lambda'=510 nm

We have to find the speed of physicist traveling according to his own testimony.

We know that

\frac{\lambda}{\lambda'}=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}

Where c=3\times 10^8m/s

Substitute the values

\frac{635}{510}=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}

1.25=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}

Squaring on both sides

1.5625=\frac{1+\frac{v}{c}}{1-\frac{v}{c}}

1.5625-1.5625\frac{v}{c}=1+\frac{v}{c}

1.5625-1=\frac{v}{c}+1.5625\frac{v}{c}=\frac{v}{c}(1+1.5625)

0.5625=2.5625\frac{v}{c}

v=\frac{0.5625c}{2.5625}=\frac{0.5625\times 3\times 10^8}{2.5625}

v=6.59\times 10^7m/s

8 0
3 years ago
The frequency of a vibrating object is defined as
Molodets [167]
A is the answer I think
8 0
3 years ago
Help please............
Mamont248 [21]
It should be Coulomb’s Law.
F = K * (q1*q2)/(r^2)
Where K is (9*10^9)
q is the charges
r is the radius between them.

When working with these, also remember to break them into the x and y component forces if there are multiple and one is at a diagonal.
After doing that, add all X and Y together, then use a^2+b^2=c^2 to get the total magnitude.
3 0
3 years ago
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