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4 years ago

If the frequency of the wave is 140 hz, what is the speed of the wave?

1 answer:

4 0

If f=140hz
speed=?
wavelength=?
without all information given, it would be difficult to answer but the formula is speed=frequency ×wavelength

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Kiley, Jermaine, and Gunther are playing tug-of-war. Kiley and Jermaine are on the same side of the rope, and Gunther is on the

Ivanshal [37]

-45N because you add the side together and make it equal 0

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4 years ago

Read 2 more answers

A ball with mass 0.11 kg is thrown upward with initial velocity 10 m/s from the roof of a building 20 m high. Neglect air resist

inessss [21]

Answer:

a) $H=25.1020\ m$

b) $t=3.2838\ s$

Explanation:

Given:

mass of the ball thrown up, $m=0.11\ kg$

initial velocity of the ball thrown up, $u=10\ m.s^{-1}$

height above the ground from where the ball is thrown up, $h=20\ m$

Maximum height attained by the ball above the roof level can be given by the equation of motion.

As,

$v^2=u^2-2g.h'$

where:

$v=$ final velocity at the top height of the upward motion $=0\ m.s^{-1}$

$g=$ acceleration due to gravity

$h'=$ height of the ball above the roof

Now,

$0^2=10^2-2\times 9.8\times h'$

$h'=5.10\ m$

Therefore total height above the ground:

$H=h+h'$

$H=20+5.1020$

$H=25.1020\ m$

Now we find the time taken in raching the height $h'$ :

$v=u-gt'$

$v=$ final velocity at the top of the motion $=0\ m.s^{-1}$

So,

$0=10-9.8\times t'$

$t'=1.0204\ s$

Now the time taken in coming down to the ground from the top height:

$H=u'.t_d+\frac{1}{2} g.t_d^2$

where:

$u'=$ is the initial velocity of the ball in course of coming down to ground from the top $=0\ m.s^{-1}$

Here the direction acceleration due to gravity is same as that of motion so we are taking them positively.

$25.1020=0+0.5\times 9.8\times t_d^2$

$t_d=2.2634\ s$

Therefore the total time taken in by the ball to hit the ground after it begins its motion:

$t=t'+t_d$

$t=1.0204+2.2634$

$t=3.2838\ s$

4 0

3 years ago

PLEASE HELLPP ILL GIVE BRAINLY

AlexFokin [52]

Answer:

B ( I think so?)

Explanation:

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Coastal currents are intricately tied to winds, waves, and land formations. Winds that blow along the shoreline—longshore winds—affect waves and, therefore, currents.

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3 years ago

A stationary police car emits a sound of frequency 1240 HzHz that bounces off of a car on the highway and returns with a frequen

Tju [1.3M]

Answer

given,

frequency from Police car= 1240 Hz

frequency of sound after return = 1275 Hz

Calculating the speed of the car = ?

Using Doppler's effect formula

Frequency received by the other car

$f_1 = \dfrac{f_0(u + v)}{u}$ ..........(1)