Answer:
Explanation:
Frequency is mathematically defined as the quotient of speed divided by wavelength.
where
v-is the speed of light
-w is wavelength.
Given the speed of the wave as and the wavelength , we substitute these values in the Frequency function to solve for frequency:
Hence, the wave's frequency is
Answer:
Explanation:
average speed is distance traveled over time
v = (50 + 30(1.5)) / (2 + 1.5) = 27.1428571...
v = 27 km/hr
I believe the evidence for this theory
is that:
The orbits surrounding Jupiter are
highly elliptical which are off the plane of the ecliptic, and many of these moons
are retrograde. This is very unlikely for moons or satellites which are formed during
the planetary accretion. Hence comes the theory.
Increasing the angle of inclination of the plane decreases the velocity of the block as it leaves the spring.
- The statement that indicates how the relationship between <em>v</em> and <em>x</em> changes is;<u> As </u><u><em>x</em></u><u> increases, </u><u><em>v</em></u><u> increases, but the relationship is no longer linear and the values of </u><u><em>v</em></u><u> will be less for the same value of </u><u><em>x</em></u><u>.</u>
Reasons:
The energy given to the block by the spring =
According to the principle of conservation of energy, we have;
On a flat plane, energy given to the block = = kinetic energy of
block =
Therefore;
0.5·k·x² = 0.5·m·v²
Which gives;
x² ∝ v²
x ∝ v
On a plane inclined at an angle θ, we have;
The energy of the spring =
- The force of the weight of the block on the string,
The energy given to the block = = The kinetic energy of block as it leaves the spring =
Which gives;
Which is of the form;
a·x² - b = c·v²
a·x² + c·v² = b
Where;
a, b, and <em>c</em> are constants
The graph of the equation a·x² + c·v² = b is an ellipse
Therefore;
- As <em>x</em> increases, <em>v</em> increases, however, the value of <em>v</em> obtained will be lesser than the same value of <em>x</em> as when the block is on a flat plane.
<em>Please find attached a drawing related to the question obtained from a similar question online</em>
<em>The possible question options are;</em>
- <em>As x increases, v increases, but the relationship is no longer linear and the values of v will be less for the same value of x</em>
- <em>The relationship is no longer linear and v will be more for the same value of x</em>
- <em>The relationship is still linear, with lesser value of v</em>
- <em>The relationship is still linear, with higher value of v</em>
- <em>The relationship is still linear, but vary inversely, such that as x increases, v decreases</em>
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