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Helga [31]
3 years ago
11

Two equations are shown: Equation A y = 4 over x + 3 Equation B y = −2x − 4 Which statement best compares the graphs of the two

equations? Both are nonlinear. Both are linear. Equation A is nonlinear and Equation B is linear. Equation A is linear and Equation B is nonlinear.
SHOW WORK!!

Mathematics
2 answers:
Lostsunrise [7]3 years ago
7 0

Answer:

The answer is C.  Equation A is nonlinear and Equation B is linear.

Hope This Helps!

77julia77 [94]3 years ago
5 0
The given equations are
A. y= \frac{4}{x}+3
B. y = -2x - 4

Equation A is nonlinear.
Equation B is linear.
The graphs are shown below.

Answer:
Equation A is nonlinear and equation B is linear.

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HURRY!!!! I NEED HELP RIGHT NOW!!! THIS IS TO ALL OF THOSE MATH WIZARDS OUT THERE!!
iren [92.7K]

Answer:

−9.333

Step-by-step explanation:

(1): "6.75" was replaced by "(675/100)"

(675/100)+3/8*x-((13)*1/4)=0

Simplify   1/4

675  3         1

 (———+(—•x))-(13•—)  = 0  

  100  8         4

       3

Simplify   —

           8

Equation at the end of step

2

:

  675     3          13

 (——— +  (— • x)) -  ——  = 0  

  100     8          4  

STEP

3

:

           27

Simplify   ——

           4  

Equation at the end of step

3

:

  27    3x     13

 (—— +  ——) -  ——  = 0  

  4     8      4            

3 0
3 years ago
Read 2 more answers
Help me out thank you so much whoever does!!
Helga [31]
Answer : 45 degrees

Explanation: it forms a right triangle and a right triangle is 90 degrees and the other half is 45 so that means the 2nd half is 45 degrees
8 0
3 years ago
Read 2 more answers
In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!
g100num [7]

the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

Step-by-step explanation:

   x^{3} = - 64

   x^{3} +64  = 0

   We can write 64 as  4^{3}

  x^{3} + 4^{3} = 0

  using the identity  ( x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} ) )

we get,

  = (x+4) (x^{2} -x*4+4^{2} )

  = (x+4)(x^{2} -4x+16)    ....................(1)

 solving the quadratic equation  ,

   x^{2} -4x+16 =0

solutions of this quadratic equation can be obtained by

   x=-b +- \sqrt{b^{2}-4ac } /2a

let use y for factors

x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16}  / 2*x^{2}

x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}

x=4+-\sqrt{16-64}/2

x=4+-4\sqrt{3i} /2

<u />x=2+-2\sqrt{3i}    ..................(2)

from the equation 1 we have,

x-4=0

which gives solution x=4

and from equation 2 we got  x=2+-2\sqrt{3i}

so the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

3 0
3 years ago
a large study used records from canada's national health care system to compare the effectiveness of two ways to treat prostate
N76 [4]

Answer:

  • compile the list of the 300 prostate patients considering various diversities  i.e. various ages, various stages of the disease, various racial, social and economic background , various lifestyles as well.
  • divide the sample into two groups, ensuring that each group is diversified equally
  • Assign each group to the one of the two treatment procedures
  • follow up on the different group after treatment
  • compare the measurable variables from both groups after treatment in order to determine which treatment method is best

Step-by-step explanation:

A completely randomized design for this experiment can be carried out following the following steps

  • compile the list of the 300 prostate patients considering various diversities  i.e. various ages, various stages of the disease, various racial, social and economic background , various lifestyles as well.
  • divide the sample into two groups, ensuring that each group is diversified equally
  • Assign each group to the one of the two treatment procedures
  • follow up on the different group after treatment
  • compare the measurable variables from both groups after treatment in order to determine which treatment method is best
7 0
3 years ago
Write the following number in expanded and word form 5,325,603.712
creativ13 [48]
Expanded:5,000,000+300,000+20,000+5,000+600+3+0.7+0.01+0.002

Word: five million, three hundred twenty-five thousand, six hundred three and seven hundred twelve thousandths
8 0
3 years ago
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