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OleMash [197]
3 years ago
11

Find the area of the parallelogram. *

Mathematics
1 answer:
saul85 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

30hg(jn

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Find the 78th term of the arithmetic sequence<br> -12,-13,-14,
creativ13 [48]

Answer:

  -89

Step-by-step explanation:

The first term of the sequence is a1 = -12.

The common difference between terms is ...

  d = -13 -(-12) = -1

The generic term is given by ...

  an = a1 +d(n -1)

Then the 78th term is ...

  a78 = -12 +(-1)(78 -1) = -12 -77

  a78 = -89

8 0
2 years ago
What are the variables in the expression below?
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Answer:

pizza

Step-by-step explanation:

dough sauce cheese toppings ∞║║║║║║║║

3 0
3 years ago
Rectangle GHIJ is dilated to be a smaller shape. What is the name of the image after the dilation?
prisoha [69]
To know whether the shape is the pre-image or the resulting shape, we need to look at its name.

In this instance, the name of the pre-image is GHIJ.

The resulting name of the shape would be G'H'I'J'.

An apostrophe is placed after every letter to signify that it is the resulting coordinate of the original.
8 0
4 years ago
Read 2 more answers
What is obtained by squaring the standard deviation?
anastassius [24]
<h2>Answer:</h2>

Variance

<h2>Step-by-step explanation:</h2>

The standard deviation is related to the variance. The standard deviation measures the variation or dispersion of a set of data and is represented by the Greek letter sigma \sigma, while the variance measures how far a set of  numbers are spread out from their average value. The variance is obtained by squaring the standard deviation, so the variance can be found as \sigma^{2}

3 0
3 years ago
Write and equation of the translated or rotated graph in general form (picture below)
WINSTONCH [101]

Answer:

The answer is hyperbola; (x')² - (y')² - 16 = 0 ⇒ answer (a)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

 xy = -8

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* The equation xy = -8

∵ We have term xy that means we rotated the graph about

  the origin by angle Ф

∵ Ф = π/4

∴ We rotated the x-axis and the y-axis by angle π/4

* That means the point (x' , y') it was point (x , y)

- Where x' = xcosФ - ysinФ and y' = xsinФ + ycosФ

∴ x' = xcos(π/4) - ysin(π/4) , y' = xsin(π/4) + ycos(π/4)

∴ x' = x/√2 - y/√2 = (x - y)/√2

∴ y' = x/√2 + y/√2 = (x + y)/√2

* Lets substitute x' and y' in the 1st answer

∵ (x')² - (y')² - 16 = 0

∴ (\frac{x-y}{\sqrt{2}})^{2}-(\frac{x+y}{\sqrt{2}})^{2}=

 ( \frac{x^{2}-2xy+y^{2}}{2})-(\frac{x^{2}+2xy+y^{2}}{2})-16=0

* Lets open the bracket

∴ \frac{x^{2}-2xy+y^{2}-x^{2}-2xy-y^{2}}{2}-16=0

* Lets add the like terms

∴ \frac{-4xy}{2}-16=0

* Simplify the fraction

∴ -2xy - 16 = 0

* Divide the equation by -2

∴ xy + 8 = 0

∴ xy = -8 ⇒ our equation

∴ Answer (a) is our answer

∴ The answer is hyperbola; (x')² - (y')² - 16 = 0

* Look at the graph:

- The black is the equation (x')² - (y')² - 16 = 0

- The purple is the equation xy = -8

- The red line is x'

- The blue line is y'

6 0
3 years ago
Read 2 more answers
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