Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and
.
To find:
The
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]


In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
We know that base angles of an isosceles triangle are congruent.
[Base angles of an isosceles triangle]


In triangle AOB,





Therefore, the measure of angle AOB is 120 degrees.
If the gradient is -2 that just means we work back the way, the method i use to find the gradient is y^2-y^1/x^2-x^1 so if we sub the variables in that gives us -18-(-8)/3-x so if we add that up we get -10/3-x, so what has to be on the bottom to get -2? in this case it would be -2 so the overall answer would be -10/5 which would give us a slope of -2 when simplified :) hope this helps
Answer:
Slope is 1/2
Step-by-step explanation:
Slope Formula = m = y2 - y1/x2 - x1
Point = (4,2) and (10,5)
m = y2 - y1/x2 - x1
m = 5 - 2/10 - 4
m = 3/6
m = 1/2
The answer is going to be c