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Brilliant_brown [7]
3 years ago
11

An athlete plains to run 3 miles. Each lap around th school yard is 3/7 miles how many laps will the athlete run

Mathematics
1 answer:
kati45 [8]3 years ago
3 0

Answer: 7 laps

Step-by-step explanation:

The athlete planned to run 3 miles

1 lap = 3/7 miles

x laps = 3 miles

by proportion :

x × 3/7miles = 3 miles

x = 3 ÷ 3/7

x = 3 x 7/3

x = 7

Therefore: the athlete will run 7 laps

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Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

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This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

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