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BabaBlast [244]
3 years ago
5

Suppose your drama club is planning a production that will cost $525 for the set and $150 per performance. A sold-out performanc

e will bring in $325. Write an equation for the cost C and an equation for the income I for p sold-out performances. Find how many sold-out performances will make the cost equal to the income.
Mathematics
2 answers:
Montano1993 [528]3 years ago
8 0

Answer:

3 sold out performances

Step-by-step explanation:

Let p be the sold out performances.

drama club is planning a production that will cost $525 for the set and $150 per performance

So cost is 150p +525

A sold-out performance will bring in $325

So Income is 325 p

Now we make cost = income

150p +525=325 p

Subtract 150 p from both sides

525=175 p

Divide 175 on both sides

p=3

So 3 sold out performances

Dimas [21]3 years ago
4 0

<em>C = I</em>

<em>150p + 525 = 325p</em>

<em> 525 = 175p</em>

p = 3


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Step-by-step explanation:

Parallel lines have:

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The formula of the slope of a line which passes through points (x_{1},y_{1}) and (x_{1},y_{1}) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ The given line passes through points (-12 , -2) and (0 , -4)

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- Use the formula of the slope above to find the slope of the given line

∵ m=\frac{-4-(-2)}{0-(-12)}=\frac{-4+2}{12}=\frac{-2}{12}=\frac{-1}{6}

∴ The slope of the given line is \frac{-1}{6}

∵ The two lines are parallel

∴ Their slopes are equal

∴ The slope of the parallel line = \frac{-1}{6}

∵ The parallel line passes through point (0 , 6)

- The form of the linear equation is y = mx + b, where m is the slope

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∵ m = \frac{-1}{6} and b = 6

∴ The equation of the parallel line is y = \frac{-1}{6} x + 6

Let us check which point is on the line by substitute the x in the equation by the x-coordinate of each point to find y, if y is equal the y-coordinate of the point, then the point is on the line

Point (-12 , 8)

∵ x = -12 and y = 8

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∴ Point (-12 , 8) is on the line

Point (-12 , 8) is on the line that passes through (0, 6) and is parallel to the given line

Learn more:

You can learn more about the equations of parallel lines in brainly.com/question/9527422

#LearnwithBrainly

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Thus,

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Let us check if we can reduce the fraction \frac{333}{1000}

For this, we need to find a common factor of 333 and 1000 in order to cancel it out.

But, first, we need to find the Greatest Common Divisor (GCD) of 333, 1000

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Prime Factorization of 333:      3 · 3 · 37

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As there is no common factor for 333 and 1000, therefore, the GCD is 1.

Important Tip:

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