Answer:
From the graph: we have the coordinates of RST i.e,
R = (2,1) , S = (2,-2) , T = (-1,-2)
Also, it is given the scale factor
and center of dilation C (1,-1)
The mapping rule for the center of dilation applied for the triangle as shown below:
![(x, y) \rightarrow (\frac{2}{3}(x-1)+1, \frac{2}{3}(y+1)-1)](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%5Crightarrow%20%28%5Cfrac%7B2%7D%7B3%7D%28x-1%29%2B1%2C%20%5Cfrac%7B2%7D%7B3%7D%28y%2B1%29-1%29)
or
or
![(x, y) \rightarrow (\frac{2}{3}x+\frac{1}{3} , \frac{2}{3}y-\frac{1}{3} )](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%5Crightarrow%20%28%5Cfrac%7B2%7D%7B3%7Dx%2B%5Cfrac%7B1%7D%7B3%7D%20%2C%20%5Cfrac%7B2%7D%7B3%7Dy-%5Cfrac%7B1%7D%7B3%7D%20%29)
Now,
for R = (2,1)
the image R' =
or
![(\frac{4}{3}+\frac{1}{3} , \frac{2}{3}-\frac{1}{3} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B4%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B3%7D%20%2C%20%5Cfrac%7B2%7D%7B3%7D-%5Cfrac%7B1%7D%7B3%7D%20%29)
⇒ R' =
For S = (2, -2) ,
the image S'=
or
![(\frac{4}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B4%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B3%7D%20%2C%20%5Cfrac%7B-4%7D%7B3%7D-%5Cfrac%7B1%7D%7B3%7D%20%29)
⇒ S' =
and For T = (-1, -2)
The image T' =
or
![(\frac{-2}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B-2%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B3%7D%20%2C%20%5Cfrac%7B-4%7D%7B3%7D-%5Cfrac%7B1%7D%7B3%7D%20%29)
⇒ T' = ![(\frac{-1}{3} , \frac{-5}{3})](https://tex.z-dn.net/?f=%28%5Cfrac%7B-1%7D%7B3%7D%20%2C%20%5Cfrac%7B-5%7D%7B3%7D%29)
Now, label the image of RST on the graph as shown below in the attachment:
Answer:
See explaination for the details of the answer
Step-by-step explanation:
Defect per opportunity DPO = defects/ no. of opportunities = 2/25 = 0.08
Defect per million opportunities
DPMO = DPO * 1 million
DPMO = 0.08 * 1 million = 80,000
six sigma = 2.9, take the dpmo at higher level if not exact 80800 for 2.9
If you are talking about the binomial being expanded then it would be:
8x^3 + 12x^2y + 6xy^2 + y^3
The y in the second term is not part of the exponent
And since you are raising the binomial to the third, you would be using the third row of Pascal's triangle.
Hope this helped!
There's some unknown (but derivable) system of equations being modeled by the two lines in the given graph. (But we don't care what equations make up these lines.)
There's no solution to this particular system because the two lines are parallel.
How do we know they're parallel? Parallel lines have the same slope, and we can easily calculate the slope of these lines.
The line on the left passes through the points (-1, 0) and (0, -2), so it has slope
(-2 - 0)/(0 - (-1)) = -2/1 = -2
The line on the right passes through (0, 2) and (1, 0), so its slope is
(0 - 2)/(1 - 0) = -2/1 = -2
The slopes are equal, so the lines are parallel.
Why does this mean there is no solution? Graphically, a solution to the system is represented by an intersection of the lines. Parallel lines never intersect, so there is no solution.
Step-by-step explanation:
5x = 19 - 4
5x = 15
x = 15/ 5
= 3
hope it helps!