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3 years ago

How would I find x?

Mathematics

1 answer:

lidiya [134]3 years ago

5 0

Answer:

f(x) = y

Step-by-step explanation:

f(x) always equals y, so the equation would be y = 7. therefore, I am pretty sure that x = y, but you may want to wait to ask your teacher. If there is more detail, message me!

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Please help and get points

stich3 [128]

2/4 and 1/4, 2x3=6 4x2=8, 3x1=3 3x4=12

7 0

3 years ago

Pretty please help me ❤️pleaaaase

never [62]

Answer:

Sue = 25.75

Dave = 29.5

Tom = 19.75

Sue = s

Tom = t

Dave = d

Step-by-step explanation:

s+t+d = 75

s-6=t

d +16 = s+t

d+16+d= 75

2d = 59

d = 29.5

t = s-6

t+s = 45.5

s-6+s= 45.5

2s = 51.5

s= 25.75

t= 19.75

5 0

3 years ago

Read 2 more answers

Using the slope formula, find the slope of the line through the given points.<br> (1,6) and (3,4)

svlad2 [7]

To find slope you do y2-y1 over x2-x1. So 4-6 is -2. And 3-1 is 2. So -2/2 is -1. The slope is -1.

7 0

3 years ago

The cost y of renting a car for x days is $10.99 for each half day.

professor190 [17]

The answer is y=10.99x

8 0

3 years ago

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

3 years ago

How would I find x?​

How would I find x?