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3 years ago

How would I find x?

Mathematics

1 answer:

lidiya [134]3 years ago

5 0

Answer:

f(x) = y

Step-by-step explanation:

f(x) always equals y, so the equation would be y = 7. therefore, I am pretty sure that x = y, but you may want to wait to ask your teacher. If there is more detail, message me!

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(-6x) / (-2) Simplify. 12x 4x 3x 1/12x

ElenaW [278]

$\dfrac{-6x}{-2}=\dfrac{-6}{-2}x=3x$

8 0

3 years ago

Pls helppp me this is very very urgent

Nat2105 [25]

Answer:

1. 5040

2. 20

Step-by-step explanation:

1. using the formula for permutation

nPr=n!/(n-r)!

10P4 = 10!/(10-4)!

=10*9*8*7*6!/6!

then we are left with

=10*9*8*7

=5040

2.using the formula for combination

nCr=n!/(n-r)!r!

6C3=6!/(6-3)!3!

=6*5*4*3!/3!3!

=6*5*4/3*2*1

=20

4 0

4 years ago

Find each percent of change. Round yo the nearest whole percent if necessary. 55 to 35

Reptile [31]

So subtract 55 from 35

35 - 55 = -20

then, put -20 over 55

-20/55 equals -0.36 repeating, rounded to -0.36, which equals 36%

the negative stands for decrease, so it's around 36% decrease

8 0

3 years ago

ALGEBRAIC EXPRESSION 11. Subtract the sum of 13x – 4y + 7z and – 6z + 6x + 3y from the sum of 6x – 4y – 4z and 2x + 4y – 7. 12.

Naily [24]

Answer:

Explained below.

Step-by-step explanation:

(11)

Subtract the sum of (13x - 4y + 7z) and (- 6z + 6x + 3y) from the sum of (6x - 4y - 4z) and (2x + 4y - 7z).

$[(6x - 4y - 4z) +(2x + 4y - 7z)]-[(13x - 4y + 7z) + (- 6z + 6x + 3y) ]\\=[6x-4y-4z+2x+4y-7z]-[13x-4y+7z-6z+6x+3y]\\=6x-4y-4z+2x+4y-7z-13x+4y-7z+6z-6x-3y\\=(6x+2x-13x-6x)+(4y-4y+4y-3y)-(4z+7z+7z-6z)\\=-11x+y-12z$

Thus, the final expression is (-11x + y - 12z).

(12)

From the sum of (x² + 3y² - 6xy), (2x² - y² + 8xy), (y² + 8) and (x² - 3xy) subtract (-3x² + 4y² - xy + x - y + 3).

$[(x^{2} + 3y^{2} - 6xy)+(2x^{2} - y^{2} + 8xy)+(y^{2} + 8)+(x^{2} - 3xy)] - [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[x^{2} + 3y^{2} - 6xy+2x^{2} - y^{2} + 8xy+y^{2} + 8+x^{2} - 3xy]- [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[4x^{2}+3y^{2}-xy+8]-[-3x^{2} + 4y^{2} - xy + x - y + 3]\\=4x^{2}+3y^{2}-xy+8+3x^{2}-4y^{2}+xy-x+y-3\\=7x^{2}-y^{2}-x+y+5$