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tekilochka [14]
3 years ago
11

Do you believe that the US should convert to the metric system explain why or why notâ

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

Step-by-step explanation:

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goldenfox [79]
In 2 weeks and it will be 60 minions
8 0
3 years ago
Use the number line below to calculate 1/2x4/6:
Eddi Din [679]

Answer:

<h2>D.4/12</h2>

Step-by-step explanation:

<h3>I took the test to</h3>
4 0
2 years ago
A spring has a natural length of 7 m. If a 4-N force is required to keep it stretched to a length of 11 m, how much work W is re
bezimeni [28]

Answer:

18 J is the work required to stretch a spring from 7 m to 13 m.

Step-by-step explanation:

The work done is defined to be the product of the force F and the distance d  that the object moves:

W=Fd

If F is measured in newtons and d<em> </em>in meters, then the unit for is a newton-meter, which is called a joule (J).

This definition work as long as the force is constant, but if the force is variable like in this case, we have that the work done is given by

W=\int\limits^b_a {f(x)} \, dx

Hooke’s Law states that the force required to maintain a spring stretched x    units beyond its natural length is proportional to

f(x)=kx

where k is a positive constant (called the spring constant).

To find how much work W is required to stretch it from 7 m to 13 m you must:

Step 1: Find the spring constant

We know that the spring has a natural length of 7 m and a 4 N force is required to keep it stretched to a length of 11 m. So, applying Hooke’s Law

4=k(11-7)\\\\\frac{k\left(11-7\right)}{4}=\frac{4}{4}\\\\k=1

Thus F=x

Step 2: Find the the work done in stretching the spring from 7 m to 13 m.

Recall that the natural length is 7 m, so when we stretch the spring from 7 m to 13 m, we are stretching it by 6 m beyond its natural length.

Work needed to stretch it by 6 m beyond its natural length

W=\int\limits^6_0 {x} \, dx \\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1\\\\\left[\frac{x^{1+1}}{1+1}\right]^6_0\\\\\left[\frac{x^2}{2}\right]^6_0=18

18 J is the work required to stretch a spring from 7 m to 13 m.

5 0
3 years ago
A local telephone company offers a long-distance telephone plan that charges $5.25 per month and $0.08 per minute of calling tim
Zepler [3.9K]

Answer:

$19.09

Step-by-step explanation:

We just have to substitute t(minutes) for 173

0.08(173) + 5.25

13.84 + 5.25 = 19.09

His monthly bill would be $19.09

Nineteen dollars and 9 cents

6 0
3 years ago
Read 2 more answers
Random list of rational numbers
vagabundo [1.1K]

1/3, 2/4, 1/5, 9/3, etc....

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2 years ago
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