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tekilochka [14]
3 years ago
11

Do you believe that the US should convert to the metric system explain why or why notâ

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

Step-by-step explanation:

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Please help me if you know answer its okay but if able to could please explain step by step.
Masja [62]

Answer: The answer would be c


Step-by-step explanation:

Step 1: Solve for b

5a+b=7

b=-5a+7

your slope would be -5a

Step 2: Make it perpendicular

The Perpendicular is gonna be the opposite

So it would be b= 1/5+7

The slopes has to be different and you don't have to worry about the "+7"

Reply if you have any questions


8 0
3 years ago
Anyone know? I need help it’d be cool if someone gave the answer
photoshop1234 [79]

Answer: 19 units

Step-by-step explanation:

Count from A down then the left until you reach B.

8 0
3 years ago
Pleaseeee help!!!! I will mark you as brainlinest for correct answer!!!!!!!!
Anni [7]
I used a graphing calculator for this.

The solution my calculator got was:

(-2.625, 0.688) My calculator is very accurate, I don't think the test expects it to be like that.

Let's find the closest coordinates.

"B" is the closest.

I hope this helps!
~kaikers
5 0
3 years ago
A tree and a building stand side by side. The 5-foot tall tree cast a shadow of 12 feet. If the building is 80 feet tall, how lo
SpyIntel [72]

Answer:

The shadow of the building = 192 ft.

Step-by-step explanation:

∵ There is a proportional relation between the heights of the tree and the building and their shadows

∴ Height tree/height building = shadow tree/shadow building

\frac{5}{80}=\frac{12}{x}

x = \frac{(80)(12)}{5}= 192 ft ⇒ x is the length of the shadow of the building

3 0
3 years ago
Suppose each edge of the cube shown in the figure is 10 inches long. Find the sine and cosine of the angle formed by diagonals D
tatiyna

Check the picture below.

sin(EDG )=\cfrac{\stackrel{opposite}{10}}{\underset{hypotenuse}{10\sqrt{3}}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{sin(EDG )=\cfrac{\sqrt{3}}{\sqrt{3^2}}\implies sin(EDG )=\cfrac{\sqrt{3}}{3}} \\\\[-0.35em] ~\dotfill

cos(EDG )=\cfrac{\stackrel{adjacent}{10\sqrt{2}}}{\underset{hypotenuse}{10\sqrt{3}}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{cos(EDG )=\cfrac{\sqrt{6}}{\sqrt{3^2}}\implies cos(EDG )=\cfrac{\sqrt{6}}{3}}

4 0
2 years ago
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