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djverab [1.8K]
3 years ago
9

How many lines of symmetry does a regular decagon have? 8 10 11 12

Mathematics
2 answers:
Lady_Fox [76]3 years ago
8 0

Answer:

The regular decagon has 10 axes of symmetry.

Step-by-step explanation:

A regular decagon is made up of ten sides and ten vertices. Each vertex is located exactly in front of another vertex (opposite). Then, by drawing axes that join two opposite vertices, five axes of symmetry can be constructed.

Each side is located exactly opposite the other side of the decagon (opposite). Then, joining the midpoints of each side, with their respective opposite, five axes of symmetry are constructed for the decagon.

Conclusion: the regular decagon has 10 axes of symmetry.

bixtya [17]3 years ago
6 0
The number of sides is the same as the number of lines of symmetry and the order of rotational symmetry.

So, a regular decagon would have 10 lines of symmetry.
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Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

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\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

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\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

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\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

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\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

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\underline{\textsf{Answer:}}

Answer:

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\underline{\textsf{Find more:}}

Find more:

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