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Ksivusya [100]
3 years ago
11

2+16y=3x+4 solve for y

Mathematics
1 answer:
serg [7]3 years ago
3 0
Let's solve for y.<span><span>2+<span>16y</span></span>=<span><span>3x</span>+4</span></span>Step 1: Add -2 to both sides.<span><span><span><span>16y</span>+2</span>+<span>−2</span></span>=<span><span><span>3x</span>+4</span>+<span>−2</span></span></span><span><span>16y</span>=<span><span>3x</span>+2</span></span><span>Step 2: Divide both sides by 16.
16y/16 = 3x+2/16
Y=3/16x +1/8</span>
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Flauer [41]
The width is 35in, the length is 95in
7 0
3 years ago
Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none
Marysya12 [62]

Answer:  The required solution of the given system is

(x, y) = (3, 1)  and  (4, 0).

Step-by-step explanation:  We are given to solve the following system of equations :

x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

From equation (i), we have

x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

Substituting the value of y from equation (iii) in equation (ii), we get

y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.

When, x = 3, then from (iii), we get

y=4-3=1.

And, when x = 4, then from (iii), we get

y=4-4=0.

Thus, the required solution of the given system is

(x, y) = (3, 1)  and  (4, 0).

8 0
3 years ago
PLEASE HELP WILL MARK BRAINIEST!!!!!!!!
Levart [38]

Answer:

A.

Step-by-step explanation:

4 0
3 years ago
What is the simplified form of x+2/x^2-3x-10 * x-3/x^2+x-12
Vinvika [58]
I mean based on your possible answers, the third one is correct,but you can go further that that, in the steps i will note when you've came to the "answer"

\frac{x + 2}{  {x}^{2}  - 3x - 10  }  \times  \frac{x - 3}{ {x}^{2} + x - 12 }
\frac{x + 2}{ {x}^{2} + 2x - 5x - 10 }  \times  \frac{x - 3}{ {x}^{2} + 4x - 3x - 12 }
\frac{x + 2}{x(x + 2) - 5(x + 2)}  \times  \frac{x - 3}{x(x + 4) - 3(x + 4)}
\frac{x + 2}{(x + 2) \times (x - 5)}  \times  \frac{x - 3}{(x + 4) \times (x  - 3)}
\frac{1}{(x + 4) \times (x + 5)}
and basically that's the "answer", but you can simplify more.

\frac{1}{ {x}^{2}  + 4x - 5x - 20}
\frac{1}{ {x}^{2} - x - 20 }
Hope that's helpful
3 0
3 years ago
Henlo! <br> how is everyone doing?<br> OK 15 points<br> name all the colors in the rainbow!
GuDViN [60]

Answer:

red

orange

yellow

green

blue

purple

Step-by-step explanation:

thanks for the points

4 0
2 years ago
Read 2 more answers
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