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harkovskaia [24]
2 years ago
6

A triangle has two sides of lengths 5 and 12 what value could the length of the third party be check all apply

Mathematics
2 answers:
choli [55]2 years ago
3 0
The third side must be greater than the difference of the other 2 sides and less than the sum of the other 2 sides.
5 and 12 SUM = 17
DIFFERENCE = 7

The 3rd side must be greater than 7 and less than 17

So, the third side could be 9 or 11.

Source:
http://www.1728.org/trianinq.htm


Scorpion4ik [409]2 years ago
3 0

Answer: 11 and 9

Step-by-step explanation:

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Consider the curve defined by 2x2+3y2−4xy=36 2 x 2 + 3 y 2 − 4 x y = 36 .
8_murik_8 [283]

Answer:

Step-by-step explanation:

Given a curve defined by the function 2x²+3y²−4xy=36

The total differential of this function with respect to a variable x makes the function an implicit function because it contains two variables.

Differentiating both sides of the equation with respect to x we have:

4x+6ydy/dx-(4xd(y)/dx+{d(4x)/dx(y))} = 0

4x + 6ydy/dx -(4xdy/dx +4y) = 0

4x + 6ydy/dx - 4xdy/dx -4y = 0

Collecting like terms

4x-4y+6ydy/dx - 4xdy/dx = 0

4x-4y+(6y-4x)dy/dx = 0

4x-4y = -(6y-4x)dy/dx

4y-4x = (6y-4x)dy/dx

dy/dx = (4y-4x)/6y-4x

dy/dx = 2(2y-2x)/2(3y-2x)

dy/dx = 2y-2x/3y-2x proved!

5 0
3 years ago
PLEASE HELP ME ASAP!!!!
kirill115 [55]

Answer:

y=  5x + 3

Step-by-step explanation:

This is because you solve for slope, which is 5, then plug that into point slope form to get:

y - 8 = 5(x - 1)

y - 8 = 5x - 5

y = 5x  + 3.

6 0
3 years ago
Read 2 more answers
Pleasee helpp<br><br> Write a^3 •a^4 without the exponents
Sliva [168]

Answer:

a x a x a x a x a x a x a

Step-by-step explanation:

a^3 is three a's being multiplied by each other. a^4 is four a's being multiplied by each other

5 0
2 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
Evaluate-2x3 - 2x2 - 4x-2 for x=-2.<br> A.-18<br> B. 16<br> C. -2<br> D. 14
dmitriy555 [2]

Answer:

14

Step-by-step explanation:

-2x^3 - 2x^2 - 4x-2

Let x = -2

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Exponents first

-2 (-8) -2 (4) -4(-2) -2

Then multiply

16 -8 +8 -2

Then add and subtract

14

4 0
2 years ago
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