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Sergio [31]
3 years ago
14

The table shows the results of an experiment in which the spinner shown above was spun 50 times. Find the experimental probabili

ty of each outcome.
not shaded
Mathematics
1 answer:
torisob [31]3 years ago
5 0

Answer:

P(x < 4) = \frac{9}{50}

Step-by-step explanation:

Given

n(S) = 50

See attachment for distribution

Required

P(x < 4)

This is calculated as:

P(x < 4) = \frac{n(1) + n(2) + n(3)}{n(S)}

Using the data on the frequency distribution table, we have:

P(x < 4) = \frac{4 + 2 + 3}{50}

P(x < 4) = \frac{9}{50}

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Answer:

A. The first graph

Step-by-step explanation:

When you graph these two equations on a graphing calc, you should be able to see one dotted line and one solid, as well as the solutions being mostly in the 1st quadrant.

7 0
4 years ago
In 1943​, an organization surveyed 1100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alc
Fynjy0 [20]

Answer:

We conclude that the proportion of adults who totally abstain from alcohol​ has changed.

Step-by-step explanation:

We are given that in 1943​, an organization surveyed 1100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alcoholic​ beverages?"

Of the 1100 adults​ surveyed, 429 indicated that they were total abstainers. In a recent​ survey, the same question was asked of 1100 adults and 352 in

<u><em>Let p = proportion of adults who totally abstain from alcohol.</em></u>

where, p = \frac{429}{1100} = 0.39

So, Null Hypothesis, H_0 : p = 39%      {means that the proportion of adults who totally abstain from alcohol​ has not changed}

Alternate Hypothesis, H_A : p \neq 39%      {means that the proportion of adults who totally abstain from alcohol​ has changed}

The test statistics that would be used here <u>One-sample z proportion statistics</u>;

                    T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adults who totally abstain from alcohol = \frac{352}{1100} = 0.32

           n = sample of adults surveyed = 1100

So, <u><em>test statistics</em></u>  =  \frac{0.32-0.39}{\sqrt{\frac{0.32(1-0.32)}{1100} } }  

                              =  -4.976

The value of z test statistics is -4.976.

<em>Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.</em><em> </em>

<em>Since our test statistics doesn't lie within the range of  critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the proportion of adults who totally abstain from alcohol​ has changed.

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Step-by-step explanation:

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