If the triangle is isosceles and b is greater than a then,
(c) AC = BC is false.
An isosceles triangle in geometry is one with at least two equal-length sides. It can be defined as having exactly two equal-length sides or as having at least two equal-length sides, with the equilateral triangle being an exception to the second definition.
The triangle is an isosceles triangle and angle b is greater than angle b.
For option (A),
AB = BC, therefore a = c which is possible.
For option (B),
AB = AC, therefore b = c which is also possible.
For option (C),
AC = BC, therefore a =b.
But we have b > a. Hence AB = BC is false.
For option (D),
a = c, therefore AB = BC which is possible according to the properties of an isosceles triangle.
Option (C) is false.
Learn more about isosceles triangle here:
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The complete question is mentioned below:
Figure not drawn to scale. The triangle above is isosceles and b > a. Which of the following must be FALSE?
A) AB = BC
B) AB = AC
C) AC = BC
D) a = c
The distributive property says that a(b+c)= ab+ac
3(2y-7)= 3(2y)+ 3(-7)
Final answer: 6y-21
Logic is a deceptive argument. It is useful in marketing products and creating advertisements
I think because logic is idea used from brain.
False, both lines are oblique (diagonal) so they meet at some point on a graph. They can only have no solutions if the lines are parallel/have the same slope.
Am I supposed to be figuring out what the length of the two other legs are?
