yes the number is is proportional . 3$ a rose in sets of 3 and up . that give you a price for 15 at 45 $ so the cost of 30 Rose's would be 90$.
Answer:
Step-by-step explanation:
this is a set problem (mathematical set)
30 students played soccer
9 students played cricket and soccer
x students played neither cricket nor soccer
3x students played cricket only.
we can see that in the first set 21 appears and in the middle of the set 9 because it says 30 students played soccer adding x and 3x we have the following formula
30 + x + 3x = 50 where x is equal to 5 then ask us Determine the number of students who played cricket. then the value would be 3x + 9 = (3x5) + 9 = 24
S^2 + s^2 = 9^2 => 2s^2 = 81 => s^2 = 81/2 => side length s = 9(sqrt(2))/2 = 6.37 cm.
Answer:
$32000
Step-by-step explanation:
Let last years salary was $x
Therefore,
x + 3% of x = $32960
x + 0.03x = $32960
1.03x=$32960
x = 32960/1.03
x = $32,000
So, last year's salary was $32000.
Answer: ![3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Work Shown:
![\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E%7B6%7Dy%5E%7B4%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%2B3%7Dy%5E%7B3%2B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%7D%2Ax%5E%7B3%7D%2Ay%5E%7B3%7D%2Ay%5E%7B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B2%2A3%7D%2Ay%5E%7B3%7D%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%7D%2A%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Explanation:
As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.
