The value from the set {3,8,9,14} makes the equation 2n - 5 = 11 true is n = 8
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Given the equation:
2n - 5 = 11
When n = 3:
2(3) - 5 = 1 ≠ 11
When n = 8:
2(8) - 5 = 11
When n = 9:
2(9) - 5 = 13
When n = 14:
2(14) - 5 = 23
The value from the set {3,8,9,14} makes the equation 2n - 5 = 11 true is n = 8
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Answer:
A) A[p(t)] = 36πt²
B) 7234.56 square units
Step-by-step explanation:
<u>Given functions</u>:

<u>Part A</u>
To find the area of the circle of spilled paint as a function of time, substitute the function p(t) into the given function A(p):
![\begin{aligned}A(p) & = \pi p^2\\\\ \implies A[p(t)] & = \pi [p(t)]^2\\& = \pi (6t)^2\\& = \pi 6^2 t^2\\& = 36\pi t^2\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7DA%28p%29%20%26%20%3D%20%5Cpi%20p%5E2%5C%5C%5C%5C%20%5Cimplies%20A%5Bp%28t%29%5D%20%26%20%3D%20%5Cpi%20%5Bp%28t%29%5D%5E2%5C%5C%26%20%3D%20%5Cpi%20%286t%29%5E2%5C%5C%26%20%3D%20%5Cpi%206%5E2%20t%5E2%5C%5C%26%20%3D%2036%5Cpi%20t%5E2%5Cend%7Baligned%7D)
<u>Part B</u>
Given
Substitute the given values into the equation for A[p(t)} found in part A:
![\begin{aligned}A[p(8)] & = 36\pi t^2\\& = 36 \cdot 3.14 \cdot 8^2\\& = 36 \cdot 3.14 \cdot 64\\& = 113.04 \cdot 64\\& = 7234.56\:\: \sf square\:units\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7DA%5Bp%288%29%5D%20%26%20%3D%2036%5Cpi%20t%5E2%5C%5C%26%20%3D%2036%20%5Ccdot%203.14%20%5Ccdot%208%5E2%5C%5C%26%20%3D%2036%20%5Ccdot%203.14%20%5Ccdot%2064%5C%5C%26%20%3D%20113.04%20%5Ccdot%2064%5C%5C%26%20%3D%207234.56%5C%3A%5C%3A%20%5Csf%20square%5C%3Aunits%5Cend%7Baligned%7D)
Therefore, the area of spilled paint after 8 minutes if 7234.56 square units.
Given :
Amount, A = 5760 Rs.
Interest in the amount, I = 1526 Rs.
To Find :
We need to find the % rate of interest.
Solution :
Let, us assume it is simple interest.
So,

Hence, this is the required solution.
Answer:
D. Vertical Multiplication
Step-by-step explanation:
It would actually look like
3y^3 - 2y^3
× y^2 + y
weekly salary is 650$
the number of days in a week is 7.
7 days salary is 650$
one day salary is 650/7
the number of days in semi month is 30/2 = 15 days
so the salary of semi month is 15*650/7 = 1392.85 $
so the salary of semi month is 1392.85 $.