Answer:
The corresponding side in the smaller figure is 9 cm
Step-by-step explanation:
Notice that you can use proportions to solve this problem:
The ratio from large image to smaller is: Larger/smaller = 4/3.
Therefore use this type of proportions to find the length of the corresponding side to 12 cm in the smaller figure:

Answer: 0.875
i hope this helps you could also go to your calculator and type it in, but glad to help if i did
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The graph of a line with negative slope goes down to the right. The line would still go through the origin. An example is attached.
Let's consider an arbitrary 2x2 matrix as an example,

The columns of

are linearly independent if and only if the column vectors

are linearly independent.
This is the case if the only way we can make a linear combination of

reduce to the zero vector is to multiply the vectors by 0; that is,

only by letting

.
A more concrete example: suppose

Here,

and

. Notice that we can get the zero vector by taking

and

:

so the columns of

are not linearly independent, or linearly dependent.
Answer: Option A
50 minutes
Step-by-step explanation:
Observe in the diagram that the vertical axis represents the score obtained and the horizontal axis represents the study time.
To find out how many hours the person with a score of 81 studied, locate the point that is at a vertical distance of 81.
Now draw a vertical line from this point to the horizontal axis. Note that the vertical line traced intercepts the vertical axis at x= 50
Then the person who got a score of 81 studied 50 minutes
The answer is the option A