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Temka [501]
4 years ago
14

Kite ABCD has a longer diagonal AC with a length of 14 in. and a shorter diagonal BD with a length of 8 in. The diagonals inters

ect at point E. What is the length of BE?
4 in
7 in
8 in
14 in
Mathematics
1 answer:
mash [69]4 years ago
7 0
Hello,
The longer diagonal is an axis of symmetry of the  Kite.
So E is the middle of BD and BE=8/2=4

Answer A: 4in.
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What is the answer to 5-3x=1-x ??
DaniilM [7]
The correct answer is 6
8 0
3 years ago
On a given day, 36 of the 445 students in a school were absent. What was the appproximate absentee rate that day?
Nata [24]

Answer: The approximate absentee rate that day would be 8.09%.

Step-by-step explanation:

Since we have given that

Number of students who were absent = 36

Total number of  students = 445

We need to find the approximate absentee rate that day :

Rate of absentee of that day would be

\dfrac{\text{Number of absentee}}{\text{Total number of students}}\times 100\\\\=\dfrac{36}{445}\times 100\\\\=8.09\%

Hence, the approximate absentee rate that day would be 8.09%.

5 0
3 years ago
What is the solution to sqrt 17-x=x+3? Show your work.
snow_lady [41]

Answer:

x=1

Step-by-step explanation:

Remember:

(\sqrt[n]{a})^n=a\\\\(a+b)=a^2+2ab+b^2

Given the equation \sqrt{17-x}=x+3, you need to solve for the variable "x" to find its value.

You need to square both sides of the equation:

(\sqrt{17-x})^2=(x+3)^2

17-x=(x+3)^2

Simplifying, you get:

17-x=x^2+2(x)(3)+3^2\\\\17-x=x^2+6x+9\\\\x^2+6x+9+x-17=0\\\\x^2+7x-8=0

Factor the quadratic equation. Find two numbers whose sum be 7 and whose product be -8. These are: -1 and 8:

(x-1)(x+8)=0

Then:

x_1=1\\x_2=-8

Let's check if the first solution is correct:

\sqrt{17-(1)}=(1)+3

4=4 (It checks)

Let's check if the second solution is correct:

\sqrt{17-(-8)}=(-8)+3

5\neq-5 (It does not checks)

Therefore, the solution is:

x=1

3 0
3 years ago
67. The line contains the point (4,0) and is parallel<br> to the line defined by 3x = 2y.
olganol [36]

Answer:

y=\frac{3}{2} x-6

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form:
  • y=mx+b where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
  • Parallel lines will always have the same slope but different y-intercepts.

<u>1) Determine the slope of the parallel line</u>

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

3x = 2y

Switch the sides

2y=3x

Divide both sides by 2 to isolate y

\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x

Now that this equation is in slope-intercept form, we can easily identify that \frac{3}{2} is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope \frac{3}{2} . Plug this into y=mx+b:

y=\frac{3}{2} x+b

<u>2) Determine the y-intercept</u>

y=\frac{3}{2} x+b

Plug in the given point, (4,0)

0=\frac{3}{2} (4)+b\\0=6+b

Subtract both sides by 6

0-6=6+b-6\\-6=b

Therefore, -6 is the y-intercept of the line. Plug this into y=\frac{3}{2} x+b as b:

y=\frac{3}{2} x-6

I hope this helps!

7 0
3 years ago
Can someone help me please
telo118 [61]
It's a reflection across the x axis, so the y intercept won't change (12)

f (x) = 3x + 12
 |
\/
g(x) = -3x + 12

I MAY BE WRONG IM ONLY 80% SURE
8 0
3 years ago
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