Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
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Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
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Answer:
Area: 135 ft^2
Perimeter: 50 ft
Step-by-step explanation:
area:
take the rectanle so length 12 x 9 = 108 so that is the length of the rectangle and now we need to find that of the triangle left over
subract 18 - 12 = 6 so that is the base of the trianle and we know the side length is 9 so plus it in A = (9)(6)/2
A = 54/2
A = 27
add 27 + 108 to get the total area
135
perimeter:
18 + 9 + 11 + 12 = 50
A triangle is 180 degrees. Depending on their angles: Right Angle - 90 degrees
Acute Angle - less than 90 degrees and Obtuse Angle greater than 90 degrees and under 180 degrees. Hope that helps.
Answer:
1 i koow
Step-by-step explanation:
