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3 years ago

5

Talya so go to swim 30 miles over the summer she plans to swim 3/ 4 miles per detail she reaches her goal how many days will it

take Tyann to reach her goal

1 answer:

natka813 [3]3 years ago

6 0

The answer would be 40 days

We achieve this answer by dividing the distance of the trip, 30 miles, by the distance traveled per day, 3/4 miles.

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What is the equation of a line that passes through the point (9, −3) and is parallel to the line whose equation is 2x−3y=6 ?

vlabodo [156]

2x - 3y = 6
-3y = -2x + 6
y = 2/3x - 2....the slope here is 2/3. A parallel line will have the same slope

y = mx + b
slope(m) = 2/3
(9,-3)...x = 9 and y = -3
now we sub and find b, the y int
-3 = 2/3(9) + b
-3 = 6 + b
-3 - 6 = b
-9 = b

so ur parallel equation is : y = 2/3x - 9 <== or 2x -3y = 27

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Answer:

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Step-by-step explanation:

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2 years ago

What is the area of the figure shown? Plz explain!

shutvik [7]

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D. ½y(x+z)

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2 years ago

Sooooo uhhh whats 2+2?

elena55 [62]

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3 years ago

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Write an equation for an ellipse centered at the origin, which has foci at ( 0 , ± 24 ) (0,±24)left parenthesis, 0, comma, plus

alexandr402 [8]

Answer:

$\frac{x^{2}}{400} + \frac{y^{2}}{976} = 1$

Step-by-step explanation:

The distance between foci with respect to origin is determined by mean of the Pythagorean Theorem:

$2\cdot c = \sqrt{(0-0)^{2}+[24-(-24)]^{2}}$

$2\cdot c = 48$

$c = 24$

The distance between origin and any of the horizontal co-vertices is:

$a = \sqrt{[10-(-10)]^{2}+(0-0)^{2}}$

$a = 20$

Now, the distance between origin and any of the vertical co-vertices is determined by the following Pythagorean relationship:

$c^{2} = b^{2} - a^{2}$

$b^{2} = a^{2} + c^{2}$

$b = \sqrt{a^{2}+c^{2}}$

$b = \sqrt{20^{2}+ 24^{2}}$

$b = 4\sqrt{61}$

Lastly, the equation of the ellipse in standard form is:

$\frac{x^{2}}{400} + \frac{y^{2}}{976} = 1$

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2 years ago