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3 years ago

A reflection of (–4, 5) over the x-axis is located in

Mathematics

2 answers:

olganol [36]3 years ago

8 0

It’s gonna be in quadrant III because the rule for x-axis is -> (x,-y).

Readme [11.4K]3 years ago

5 0

Answer:

Quadrant III

Step-by-step explanation:

(-4,5) is in the II quadrant because the x is negative and the y is positive

II I

(-,+) (+,+)

------------------------------------- X axis

III IV

(-,-) (+.-)

reflecting over the x axis means it would be in the third quadrant

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Jessica is eating a bag of sour skittles . Her friend ask her to share, and Jessica throws over an extra bag. Her friend does no

liraira [26]

Answer:

A parabola opens downward with vertex at (1,20)

Step-by-step explanation:

The function that models the height of bag of candies is

$h(t) = - 16 {t}^{2} + 32t + 4$

The graph of this function is a parabola that opens downward.

To find the maximum height of the candy bag, we complete the squares to obtain the vertex form of the function.

Factor -16 to get;

$h(t) = - 16( {t}^{2} - 2t) + 4$

Add and subtract the square of half the coefficient of t.

$h(t) = - 16( {t}^{2} - 2t + 1) + 16+ 4$

Factor the perfect square trinomial:

$h(t) = - 16( {t - 1)}^{2} + 20$

The vertex is (1,20)

This means the maximum height after 1 second is 20 feet.

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3 years ago

Which number is irrational?

julsineya [31]

Answer:

The square root of 3

Step-by-step explanation:

The other ones equal a number Ex Square root of 16 is 4 but the square root of 3 would be a large decimal

7 0

2 years ago

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A subway car travels at a rate of 32 meters per second. How far does it travel in 16 seconds? Use d= r x t

Simora [160]

Answer:

I think 512 feet in 16 seconds.

6 0

3 years ago

3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)

sveta [45]

Answer:

For the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

Step-by-step explanation:

Here, the given function are:

$f(x) = 3x^{2} - 2x+ 4\\g(x) = 5x^{2} + 6x -8$

Now, simplifying for (f-g)(x) = f(x) - g(x):

$f(x) - g(x) = (3x^{2} - 2x+ 4) - (5x^{2} + 6x -8)$

$= 3x^{2} - 2x+ 4- 5x^{2} - 6x +8$

Doing operation on LIKE TERMS, we get

f(x) - g(x) = $( 3x^{2}- 5x^{2}) + (-2x - 6x) +( 4 +8) = -2x^{2} - 8x + 12$

Hence, for the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

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3 years ago

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andrezito [222]

Answer:

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Step-by-step explanation:

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2 years ago

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