LISTEN I NEED HELP! I always have to ask my questions 3 times in order to get answered. I just need some help.

In which quadrants do solutions for the inequality y is less than or equal to two sevenths times x plus 1 exist?

hram777 [196]

Answer:

y will be in every single quadrant

Step-by-step explanation:

So we have the equation $y\leq \frac{2}{7} x+1$ first we will have to look at the equation. It says that y is less than or equal to $\frac{2}{7} x+1$ since y is less than $\frac{2}{7} x+1$ the only place the shaded area where y can be is under the line that is drawn be the equation. When the equation is graphed the y-intercept will be on positive 1 it since slope is rise over run it will look something like the file attached to this. so under the line you can see every single quadrant so that is why it would be that way

5 0

3 years ago

Anyone have a answer for this?

LiRa [457]

Answer:

36.1 meters

Step-by-step explanation:

Since this is a rectangle, the parallel sides are equal to each other, meaning we technically already know all the side lengths.

I'll choose to look at the bottom triangle in this case

30 is already there, and the other leg should be 20. Knowing this, we can plug these into the pythagorean theorem.

20 is A, 30 is B, and the missing side is C

$a^{2} + b^{2} = c^{2}\\20^{2} + 30^{2} = c^{2} \\400 + 900 = 1300 \\\sqrt{1300} = 36.06\\$

C, the missing side to the nearest tenth is 36.1 meters

7 0

3 years ago

Determine whether the given set s is a subspace of the vector space v.

Aneli [31]

Answer:

Step-by-step explanation:

3 0

4 years ago

A farmer finds that if she plants 50 trees per acre, each tree will yield 80 bushels of fruit. She estimates that for each addit

pashok25 [27]

Answer:

28

Step-by-step explanation:

From the given information:

Let x be the number of trees.

F(x) = (50 +x) (20 - 3x)

F(x) = 1000 - 150x + 20x - 3x²)

F(x) = -3x² - 130x + 1000

Differentiating F(x) with respect to x;

$F'(x) = \dfrac{d}{dx}( -3x^2- 130x + 1000)$

$F'(x) = ( -3(2x)- 130(1) +0)$

F'(x) = -6x -130

Now; we set F'(x) to be equal to zero to determine the critical value;

-6x - 130 = 0

x = - 130/6

Differentiating F''(x) with respect to x

$F''(x) = \dfrac{d}{dx}( -6x- 130)$

$F''(x) = ( -6(1))$

F''(x) = -6 (<0)

Thus; by the second derivative, the revenue function F(x) is maximum when x = -130/6

Therefore, the number of trees she should plant per acre to maximize her harvest is:

50 + x = 50 - 130/6

= 85/3

$\simeq$ 28

Therefore, the number of trees per acre to maximize the harvest is 28

6 0

3 years ago

The phythatagorean Theron in two and three dimensions

natta225 [31]

The Pythagorean theorem states that a^2 + b^2 = c^2, where a and b are sides not opposite to the right angle, shown as a square. C represents the hypotenuse, or side opposite of the right angle

We see that a = 14 (it can also be b; both can be plugged in as both are adjacent and not opposite of the right angle)

c = 19; hypotenuse is opposite of right angle

14^2 + b^2 = 19^2

196 + b^2 = 361

b^2 = 361 - 196

b^2 = 165

b = square root of 165

b = 12.845

x = 12.845

3 0

3 years ago