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Oksi-84 [34.3K]
3 years ago
5

Determine whether the given set s is a subspace of the vector space v.

Mathematics
1 answer:
Aneli [31]3 years ago
3 0

Answer:

Step-by-step explanation:

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You want to measure the height of a tree growing vertically on the side of a hill. The hill makes an angle of 20°with the horizo
seropon [69]
We need to solve for the height of the tree and we need to define the variable that would represent this value. In this case, we assign "y" for the unknown height of the tree. See attached picture for better comprehension.
Solving for the variable "a" which is base of downhill to the tree, we have it:
cos 20° = a / 15 ft
a = 15*cos 20°
a = 14.095 feet
Solving for the variable "x" which is the side of the hill to the base of the tree, we have it:
sin 20° = x / 15 ft
x = 15 * sin20°
x = 5.130 feet
Solving for the variable "y", which is the height of the tree, we have it:
tan 45° = (x+y) / a
tan 45° = (5.13 + y) / 14.095
y = 14.095*tan45° - 5.13
y = 8.965 feet

The height of the tree is 8.965 feet.

4 0
3 years ago
A train travels 540 miles in 12 hours.
egoroff_w [7]

Answer:

45 because you have to take 540 divided by 12 to get how many miles there are in one hour

Step-by-step explanation:

Hope it helps

8 0
3 years ago
Read 2 more answers
PLS HELP U WILL GET BRAINLIEST
Paraphin [41]

Answer:

The 1st option

Step-by-step explanation:

Line RT bisects VS at a right angle. We know that angle RTS is a right angle, so RTV is also a right angle.

5 0
3 years ago
The local music activities coordinator sold 300 tickets to the orchestra concert. Student tickets were $4, and adult tickets wer
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There were sold 100 student tickets

4 0
3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
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