Explanation:
Given that,
A ball is tossed straight up with an initial speed of 30 m/s
We need to find the height it will go and the time it takes in the air.
At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :
v = u +at
Here, a = -g
v = u -gt
i.e. u = gt
So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds
Let d is the maximum distance covered by it.
Putting all values
Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.
Answer:
p = 0.16 kgm/s
Explanation:
the initial momentum combined of the two cars and the final momentum of the paired cares are the same, so we just need to find the initial momentum
p = m1v1 + m2v2
p = 0.04*4 + 0.04*0
p = 0.04*4
p = 0.16 kgm/s
Answer:
Because the log is hollow or is less dense
Explanation:
If a log has little density, it will float. While sand is dense and completely solid, so it will sink.
Answer:
2.85 s .
Explanation:
y(t) = y(0) + v₀t + 1/2 gt²
y(t) is vertical displacement , y(0) is initial position , v₀ is initial velocity and t is time required to make vertical displacement and g is acceleration due to gravity.
Here y(0) is zero , v₀ = 14 m/s , g = 9.8 m s⁻² , y(t ) = 0 , as the pumpkin after time t comes back to its initial position, that is ground .
We shall take v₀ as negative as it is in upward direction and g as positive as it acts in downward direction
Put the values in the equation above,
0 = 0 - 14t + 1/2 x 9.8 t²
14 t = 1/2 x 9.8 t²
t = 28 / 9.8
t = 2.85 s .
Answer:
Acceleration = 0.9144 m/s^2
Explanation:
Initial speed = 45 ft/s
Final speed = 60 ft/s
Time = 5 sec
Acceleration = a = (v-u) / t
= 60-45 / 5
= 0.9144 m/s^2
