Answer:
The magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N
Explanation:
Given;
speed of the electron, v = 8.0 × 10⁶ m/s
magnetic field strength, B = 2.5 T
angle of inclination of the field, θ = 60°
The magnetic force experienced by the electron in the magnetic field is given as;
F = qvBsinθ
where;
q is charge of electron = 1.6 x 10⁻¹⁹ C
B is strength of magnetic field
v is speed of the electron
Substitute the given values and solve for F
F = (1.6 x 10⁻¹⁹)( 8.0 × 10⁶)(2.5)sin60
F = 2.77 x 10⁻¹² N
Thus, the magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N
Answer:
(a)
(b)
(c) 
Explanation:
Differentiating Rules:
[ m and n are the function of x]
[ here c is constant and n is function of x]
Given that,

(a)

Differentiating with respect to t

[ here
is constant]


(b)

Differentiating with respect to t


(c)

Differentiating with respect to t



Answer:
he will see the sticker because its behind a window bruh and thats a big daddy stack of greens
Explanation:
Answer:
Hooke's law describes the elastic properties of materials only in the range in which the force and displacement are proportional. Hooke's law states that the applied force F equals a constant k times the displacement or change in length x, or F = kx. the maximum extent to which a solid may be stretched without permanent alteration of size or shape, is called elastic limit
mark me brainliestt :))
Answer:
The correct option is (a).
Explanation:
Given that,
The energy of photon, E = 2.52 eV
We need to find the wavelength of the photon in nm. The formula for the energy of a photon is given by :

The nearest option is a) i.e. 492.34127 nm.