Answer:
part (a) v = 1.7 m/s towards right direction
part (b) Not an elastic collision
part (c) F = -228.6 N towards left.
Explanation:
Given,
- Mass of the first puck =

- Mass of the second puck =

- initial velocity of the first puck =

- Initial velocity of the second puck =

Part (a)
Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.
From the conservation of linear momentum,

Direction of the velocity is towards right due to positive velocity.
part (b)
Given,
Final velocity of the second puck = 
Let
be the final velocity of first puck after the collision.
From the conservation of linear momentum,

For elastic collision, the coefficient of restitution should be 1.
From the equation of the restitution,

Therefore the collision is not elastic collision.
part (c)
Given,
Time of impact = t = 
we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

Negative sign indicates that the force is towards in the left side of the movement of the first puck.