Answer:
Option (3). EF
Step-by-step explanation:
From the figure attached,
Plane defined by EAB can be represented by the face EABF of the square prism also.
Similarly, plane EFG can be represented by the face EFGH of the prism.
Now these sides EABF and EFGH are joining each other at the edge EF of the cuboid.
Therefore, intersection of the given planes is EF.
Option (3) will be the answer.
Answer:no
Step-by-step explanation:
Because on a graph (2,3) means that the point is two along and three up while (3,2) means it is 3 along and two up.
1)To construct a line parallel to line l and passing through point P our first step is to join the point and line and then draw angles in such a way so that corresponding angles are equal.
Option B is the correct construction of a line parallel to line l and passing through point P.
2) To Construct the perpendicular line to line DE at point F we cut an arc from point F to line DE in such a way it cuts line DE at two points .From these two points we draw arcs which cut each other .
Option C is the correct option to Construct the perpendicular line to line DE at point F.
3) To Construct a perpendicular from the given line segment that passes through the given point we cut two arcs on top and bottom of line segment.
Option B is the right answer.
