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3 years ago

I need help I tried answering this question but I don’t understand

Mathematics

1 answer:

Gnom [1K]3 years ago

8 0

I find it easier to do the actual computation than to try to choose the correct answer from a bunch of alternatives.

You are given the area of a rectangle, as well as the length of one side. To find the length of the other side, you must divide the given side length into the area.

Thus, the unknown side length is

1.403E(-2) cm^2
----------------------- = 0.23E2 cm, or, better, 2.3E1, or 23 cm
6.1E(-4) cm

Now that you have this info, which of the given four steps do you judge to be appropriate and which inappropriate?

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Divide. (3x4 - 3x2 - 6x - 10) = (x - 2)

alekssr [168]

Answer:

3x^3 + 6x^2 + 15x + 36 + 62 / 3x^4 +3x^2 +6x + 10

Step-by-step explanation:

Use Syenthetic Division

4 0

2 years ago

Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

ANSWER

${r}^{2} = 4 \cos2\theta$

EXPLANATION

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

We substitute

$x = r \cos( \theta)$

$y = r \sin( \theta)$

and

${x}^{2} + {y}^{2} = {r}^{2}$

This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

Factor the RHS to get:

${r}^{4} = 4{r}^{2} ({ \cos^{2}\theta } - \sin^{2}\theta)$

Divide through by r²

${r}^{2} = 4 ({ \cos^{2}\theta } - \sin^{2}\theta)$

Apply the double angle identity

$\cos^{2}\theta -\sin^{2}\theta= \cos(2 \theta)$

The polar equation then becomes:

${r}^{2} = 4 \cos2\theta$

7 0

3 years ago

Demonstrate that the digits of a perfect square cannot add to 2, 3, 5, 6, or 8

Lelu [443]

It depends on what did you mean by saying perfect square. If I've understood it correctly, I can help you with a part of your problem. The squares of mod 9 are 1,4,7 which are came from 1,2,4. Addition of the given numbers are 2,3,5,6, 8, which are exactly the part of your problem. This number, which is not shown as squares Mod 9, and thus doesn't appear as a sum of digits of a perfect square. I hope you will find it helpful.

5 0

2 years ago

there are two boxes. in the first box there are 7 cards numbered from 1 tp 7 the second box also contains 7 cards from 1-7 pick

mrs_skeptik [129]

Answer:

$\frac{6}{49}$

Step-by-step explanation:

GIVEN: There are two boxes. in the first box there are $7$ cards numbered from $1$ to $7$ the second box also contains $7$ cards from $1-7$ pick one card from each box.

TO FIND: probability that the sum of the two two cards is at least $12$ .

SOLUTION:

sample case such that sum of cards is $12$ : $(5,7),(7,5),(6,6)$

sample case such that sum of cards is $13$ : $(7,6),(6,7)$

sample case such that sum of cards is $14$ : $(7,7)$

Total sample case such that sum is atleast $12$ $=6$

Total sample cases $=49$

probability that the sum of the two two cards is at least $12$ $=\frac{\text{sample case in which sum is atleast 12}}{\text{total sample cases}}$

$=\frac{6}{49}$

probability that the sum of the two two cards is at least $12$ is $\frac{6}{49}$

8 0

2 years ago

8.27 Any quarter has a face value of $0.25. An eccentric collector offers to buy state quarters for 600% of their face value. At

Svetach [21]

Answer:

$7.50

Step-by-step explanation:

First we find what is the value at which the eccentric collector offers to buy the quarters for. We know the value at which they will buy the quarter for is 600% of the face value - which is $0.25.

Now we do some math and find the value at which the person will buy the quarter for is $1.50.

Now we multiply the value by 50 since Larry would be giving 50 quarters.

$1.50*50 = 7.50

So, Larry will receive $7.50 for selling his 50 quarters to the eccentric collector.

4 0

2 years ago

Read 2 more answers