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Serga [27]
3 years ago
10

What is the improper fraction for 8 and 3/47​

Mathematics
2 answers:
Andrews [41]3 years ago
5 0

Answer:

379/47

Step-by-step explanation:

An improper fraction is a fraction that has a larger number in the numerator than the denominator.

Remember, a fraction is numerator over denominator.

So first we need to convert 8 into x/47.

We can do this by multiplying 8 by 47/47.

8 equals 8/1 and now we can set up the expression.

8/1*47/47=376/47

We did that by multiplying the denominators together and the numerators together.

Now we add 3/47 to that.

376/47+3/47=379/47

Since there is a common denominator we just had to add the numerators together.

Therefore, the answer would be 379/47

erastovalidia [21]3 years ago
4 0

Answer:

379/47

Step-by-step explanation:

1.  Simplify

2. Reduce fraction to lowest terms

1 is the greatest common divisor of 3 and 47. The result can't be further reduced.

3.  Convert mixed number to improper fraction

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Answer:

Answer B - y=[x]+7

Step-by-step explanation:

A normal [x] function has a slope of one, a y intercept of 0, and all the other basic values.

7 changes this.

Looking at the graph, we see that the y intercept is now 7.

How can this be? x was added to by 7.

If it was subtracted, it would be -7, not postive 7.

So the answer is y=[x]+7

Hope this helps!

4 0
3 years ago
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anyanavicka [17]
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The equation of a line is y= -1/2x - 1 What is the equation of the line that is perpendicular to the first line and passes throu
LiRa [457]

Answer:

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Step-by-step explanation:

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6 0
4 years ago
Prove<br>that<br>2 cos (A +45°) cos (B-45°) = cos 2A​
wolverine [178]

Answer:

Step-by-step explanation:

2 cos(A+45)cos (B-45)

=2[cos A cos 45-sin A sin 45][cos B cos 45+sin B sin 45]

=2[cos A ×1/√2-sin A ×1/√2][cos B×1/√2+sin B×1/√2]

=2[1/√2(cos A-sin A)][1/√2(cos B-sin B]

=2×1/√2×1/√2 (cos A-sin A)(cos B+sin B)

=cosA cos B+cos A sin B-sin A cos B-sin A sin B

=cos A cos B-sin A sin B-(sin A cos B-cos A sin B)

=cos (A+B)-sin (A-B)

i think there should be A in place of B.

then

=cos (A+A)-sin (A-A)

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=cos 2A

as sin 0=0

6 0
4 years ago
How do I solve this?
statuscvo [17]
Distribute the 2 then do your loop.
5^3 = 2x+16
Then you can solve for x.
5 0
3 years ago
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