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Leviafan [203]
3 years ago
14

Following are interest rates (annual percentage rates) for a 30-year-fixed-rate mortgage from a sample of lenders in a certain c

ity. It is reasonable to assume that the population is approximately normal. 4.327, 4.461, 4.547, 4.662 , 4.365, 4.526 , 4.842 Find the upper bound of the 99% confidence interval for the mean rate.
Business
1 answer:
aalyn [17]3 years ago
5 0

Hey There!:

Sample Mean = 4.4823

SD = 0.1859

Sample Size (n) = 7

Standard Error (SE) = SD/root(n) = 0.0703

alpha (a) = 1-0.99 = 0.01

t(a/2, n-1 ) =  3.7074

Margin of Error (ME) =  t(a/2,n-1)x SE = 0.2606

99% confidence interval is given by:

Sample Mean +/- (Margin of Error)

4.4823 +/- 0.2606 = (4.222 , 4.743)

Hope this helps!

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Answer:

a) CMR=  0.6

b)CVP=0.6-$1,000

c) Profit= $5000

d) Sales $10,000

e) Break-even=$3000

f) Profit increases =$600

Explanation:

a) contribution margin ratio formula is

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b) CVP relation: profit as a function of sales revenue

Version 2:

Profit = CMR × Revenue – FC

where

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FC = fixed costs

That means

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profit = $6000-$1,000

profit =$5000

d)

profit = 0.6*Revenue-$1,000

Revenue =(profit +$1,000)/0.6

Revenue = ($5,000 +$1,000)/0.6= 10000

e)Break even is when sales are equal to the cost.  

sales revenue=variable costs+fixed costs

sales revenue=$2,000+$1,000

Break-even=$3000

f)profit increases

profit increases =0.6*Revenue-$1,000

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