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laiz [17]
4 years ago
14

Find area of a rectangle whose vertices are -6,10 -6,6 2,10 and 2,6

Mathematics
1 answer:
sergey [27]4 years ago
4 0
Find length and width

(-6,10) to (-6,6) is distance of 4 down
(-6,6) to (2,6) is distance of 8 right
(-6,10) to (2,10) is distance of 8 right
(2,10) to (2,6) is distance of  4 down

length is 8 and width is 4
area=legnth times width=4*8=32 square units
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X is 44.4 degrees and round it off to the nearest degree is 44
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3 years ago
Which of the following is a solution to the inequality below? 12 - x/11 > 8
n200080 [17]

Answer:

12 - x/11 > 8

12 -8 - x/11 > 8 -8

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Step-by-step explanation:

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3 0
3 years ago
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The gym is filled with 215 students & adults. Student tickets are $.50 and adults are $2.00. If $250.00 was collected, how m
BARSIC [14]
In order to determine the correct answer, it would be helpful to set up equations. We do as follows:

Let x = students
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Hope this answers the question. Have a nice day.
3 0
3 years ago
Please find the perpendicular line slope equation please! Thanks!
lana66690 [7]

We need to convert this equation to slope-intercept form first.

We can do that by solving for y.

x - 5y = 15

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x = 5y + 15

<em><u>Subtract 15 from both sides.</u></em>

x - 15 = 5y

<em><u>Divide both sides by 5.</u></em>

y = 1/5x - 3

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The slope of the line perpendicular to the line with a slope of 1/5 is -5.

The slope of a perpendicular line is the negative reciprocal of the original slope.

Using a graphing calculator, we know the y-intercept of the line that is perpendicular to the original line must have a y-intercept of -6 to run through the points (-2, 5).

The equation of the new line is y = -5x - 6.


5 0
3 years ago
Read 2 more answers
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