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Novosadov [1.4K]
3 years ago
14

Which expression is equivalent to 4 - (-7)

Mathematics
2 answers:
777dan777 [17]3 years ago
8 0
4+7 is equal to 4- (-7) because its a double negative so it cancels each other
ad-work [718]3 years ago
5 0
4 - (-7)

This will be the same as 4 - - 7
Which is 4 + 7
11
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Not sure how to solve this
Margarita [4]

Answer:

-3/17

Step-by-step explanation:

(7,1) and (-10,4)

slope formula: m = (y₂ - y₁) / (x₂ - x₁)

plug in data: m = (4 - 1) / (-10 - 7)

solve: 3 / -17

simplify: -3/17 (written as a fraction)

8 0
3 years ago
Write the answer to the questions below: The * means multiply.
gayaneshka [121]

Answer:

1. 1363.922

2. -52

3. 254.25

4 0
3 years ago
Classify triangle LMN choose two answers below
Mariana [72]
Acute and isosceles have a great day
8 0
3 years ago
In the diagram, the measure of angle 5 is (10x – 9)°, and the measure of angle 7 is (9x)°. What is the measure of angle 6, to th
KatRina [158]
10x-9=9x
-9=-x
x=9
angle 7 = 9*(9)=81
angle 6 = 180-81= 99
7 0
4 years ago
Read 2 more answers
What is the difference? StartFraction 2 x 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x 5 Over x cubed minus 9
Fiesta28 [93]

The expression which is equivalent to the difference of the given algebraic fraction is,

\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}

<h3>What is the difference? </h3>

Difference is the mathematical operation in which the one number is subtract from another number.

To find the difference of two fraction numbers, we find the least common factor of denominator and write the all numbers as one fraction.

The given expression in the problem is,

\dfrac{2x+5}{x^2-3x}-\dfrac{3x+5}{x^3-9x}-\dfrac{x+1}{x^2-9}

Factorize the denominator of each term as,

\dfrac{2x+5}{x(x-3)}-\dfrac{3x+5}{x(x-3)(x+3)}-\dfrac{x+1}{(x-3)(x+3)}

Here, the least common factor of the denominators is x(x-3)(x+3), therefore, the expression can be written as,

\dfrac{(x+3)(2x+5)-(3x+5)-(x)(x+1)}{x(x-3)(x+3)}\\\dfr\dfrac{2x^2+5x+6x+15-3x-5-x^2-x}{x(x-3)(x+3)}\\\dfr\dfrac{x^2+7x+10}{x(x-3)(x+3)}\\\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}

Hence, the expression which is equivalent to the difference of the given algebraic fraction is,

\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}

Learn more about the difference of two fractions here;

brainly.com/question/13222

6 0
2 years ago
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