Answer:
Step-by-step explanation:
Notice when x increases 1, y is 4 times the previous one, so
the function is like 
To determine the constant C, put any pair of (x, y)
Use x = 0, y = 0.2, so
0.2 = 
= C * 1 = C
then
9x^2+t+25=(ax+b)^2
9x^2+t+25=a^2*x^2+2abx+b^2 so
a^2=9 so a=3
b^2=25 so b=5 then
t=2ab using a and b from above
t=2*3*5=30
So the missing term is 30x
26*5 is 130
He'll have ten left over if each student in year 11 has one :) Hope this helps!
Answer:
The expression is not factorable with rational numbers
Step-by-step explanation:
Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
