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Kruka [31]
3 years ago
11

Instructions: Find the missing length ​

Mathematics
1 answer:
Alchen [17]3 years ago
3 0

Answer:√20

Step-by-step explanation:

The missing side length of the right triangle is  or about 4.47 . Explanation: When we talk about the side lengths of a right triangle,

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1. Identify the vertical asymptotes of
kaheart [24]
1. x1/2=\frac{-3\pm \sqrt{9+40} }{2}
VA(the vertical asymptotes): x=-5,  x=2
2. x1/2=\frac{9\pm \sqrt{81-72} }{2}
VA: x=3, x=6
3.  \lim_{n \to \infty}  \frac{4x}{7}=∞
There is no HA.
4. \lim_{n \to \infty} \frac{7x+1}{2x-9}= \frac{7}{9}
HA : y=7/2
5. \lim_{n \to \infty}  \frac{ x^{2} +5x+3}{4x-1} =∞
There is no HA.
6. m=\lim_{n \to \infty}  \frac{ x^{2} -4x+8}{ x^{2} +2x}
m = 1
b=\lim_{n \to \infty}  \frac{ x^{2} -4x+8- x^{2} -2x}{x+2}
b = -6
OA: y = x - 6
7. Same method:
m = 2
b = 0
OA: y = 2x
8. m = 0
There is no OA.
m = 4 
b=-1
OA: y=4x-1

7 0
3 years ago
What numbers have the same value as 5% of 35?​
Anton [14]

Answer:

5% is the same as 0.05

8 0
3 years ago
Read 2 more answers
If 5% of an item is 5$, what is the original price?<br> Answer is not 25$
STatiana [176]

Answer:

$100

Step-by-step explanation:

8 0
3 years ago
At time, t=0, Billy puts 625 into an account paying 6% simple interest. At the end of year 2, George puts 400 into an account pa
svetoff [14.1K]

Answer:

26

Step-by-step explanation:

Given that:

At time, t=0, Billy puts 625 into an account paying 6% simple interest

At the end of year 2, George puts 400 into an account paying interest at a force of interest, 1/(6+t), for all t ≥ 2.

If both accounts continue to earn interest indefinitely at the levels given above, the amounts in both accounts will be equal at the end of year n. Calculate n.

In order to calculate n;

Let K constant to be the value of time for both accounts

At  time, t=0, the value of time K when Billy puts 625 into an account paying 6% simple interest is:

K = 625 \times (1+ 0.06 K)

K = 625 +37.5 K

At year end 2; George  amount of 400 will grow at a force interest, then the value of  K = 400 \times e^{\int\limits^2_k {\dfrac{1}{6+t}} \, dx }

K =400 \times \dfrac{6+K}{6+2}

K =400 \times \dfrac{6+K}{8}

K =50 \times ({6+K})

K =300+50K

Therefore:

If K = K

Then:

625 + 37.5 = 300 +50 K

625-300 = 50 K - 37.5 K

325 = 12.5K

K = 325/12.5

K = 26

the amounts in both accounts  at the end of year n = K = 26

7 0
3 years ago
Factor completely 10x^5+4x^4+8x^3
Alex_Xolod [135]
C.

HOPE THIS WILL HELP U
6 0
3 years ago
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