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3 years ago

Write equation in general form slope of 3 and y intercept of -5

Mathematics

1 answer:

arsen [322]3 years ago

3 0

Answer:

3x - y - 5 = 0

Step-by-step explanation:

The general form of the equation of a line is

Ax + By + C = 0 ( A, B, C are integers )

first express the equation in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

here m = 3 and c = - 5, hence

y = 3x - 5 ← in slope-intercept form

subtract y from both sides

3x - y - 5 = 0 ← in general form

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Write this trinomial in factored form.<br> 8x² - 9x + 1<br> Enter the correct answar.

nadezda [96]

Answer:

(8x-1) (x-1)

Step-by-step explanation:

8x² - 9x + 1

(8x - ) (x - )

We know it is minus because we have -9x

We have +1 so both have to be -

To fill in the blanks we put 1

The only combination is 1*1 =1

(8x-1) (x-1)

Lets check

8x^2 -x -8x +1

(8x^2 -9x+1

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2 years ago

Read 2 more answers

If f(x)=3x^2+2x=1 find f(x+2)

DerKrebs [107]

Answer:

f(x+2) = 3(x+2)^2 + 2(x+2) + 1

Step-by-step explanation:

Replace x with x+2 and you get the solution above. Hope this helps!

4 0

2 years ago

Suppose that a batch of 100 items contains 6 that are defective and 94 that are not defective. If X is the number of defective i

Tcecarenko [31]

Answer:

a) P(X = 0) = 0.5223

b) P(X > 2) = 0.0125

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order that the items are selected is not important, so the combinations formula is used to solve this problem.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this problem, we have that

100 items

6 defective

94 not defective.

a) P{X=0}

None defective.

Desired outcomes

Combinations of 10 from a set of 94. So

$D = C_{94,10} = \frac{94!}{10!84!} = 9041256800000$

Total outcomes:

Combinations of 10 from a set of 100. So

$T = C_{100,10} = \frac{100!}{10!90!} = 17310309000000$

P(X = 0)

$p = \frac{D}{T} = \frac{9041256800000}{17310309000000} = 0.5223$

(b) P(X>2}.

Either two or less are defective, or more than two are defective. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 2) + P(X >2) = 1$

$P(X > 2) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

P(X = 0)

$P(X = 0) = \frac{D}{T} = \frac{9041256800000}{17310309000000} = 0.5223$

P(X = 1)

Desired outcomes

Combinations of 9 from a set of 94(non defecive) and 1 from a set of 6(defective). So

$D = C_{84,9}*C_{6,1} = \frac{94!}{9!85!}*\frac{6!}{1!5!} = 6382063700000$

Total outcomes:

Combinations of 10 from a set of 100. So

$T = C_{100,10} = \frac{100!}{10!90!} = 17310309000000$

P(X = 1)

$P(X = 1) = \frac{D}{T} = \frac{6382063700000}{17310309000000} = 0.3687$

P(X = 2)

Desired outcomes

Combinations of 8 from a set of 94(non defecive) and 2 from a set of 6(defective). So

$D = C_{94,8}*C_{6,2} = \frac{94!}{8!86!}*\frac{6!}{2!4!} = 1669726000000$

Total outcomes:

Combinations of 10 from a set of 100. So

$T = C_{100,10} = \frac{100!}{10!90!} = 17310309000000$

P(X = 2)

$P(X = 2) = \frac{D}{T} = \frac{1669726000000}{17310309000000} = 0.0965$

Finally

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.5223 + 0.3687 + 0.0965 = 0.9875$

$P(X > 2) = 1 - P(X \leq 2) = 1 - 0.9875 = 0.0125$

4 0

2 years ago

8 and a y-intercept of 8.

Rudiy27

8 and a y-intercept of 8.

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2 years ago

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Solve the following 37/5+65/32

Temka [501]

Hi there!

<u>Here's the answer;</u>

37/5+65/32 =

9.43125.

Hope this helps, if it does, please consider marking me brainiest! <3

6 0

2 years ago