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Likurg_2 [28]
4 years ago
7

Find the indicated real n roots of a N=4, a=81

Mathematics
2 answers:
ella [17]4 years ago
6 0

81|3\\27|3\\.\ 9|3\\.\ 3|3\\.\ 1|\\\\81=\underbrace{3\cdot3\cdot3\cdot3}_{4}=3^4\\\\\sqrt[4]{81}=\sqrt[4]{3^4}=3\\\\Used:\\\sqrt[n]{a^n}=a

Mariana [72]4 years ago
3 0

If I understood coorectly, you're looking for the fourth root of 81. This exercise can be solved by remembering that extracting the fourth root of a number is the same as raising that number to the power of 1/4.


We also need the prime factorization of 81, which is


81 = 9 \times 9 = 3^2 \times 3^2 = 3^4


So, the fourth root of 81 is 81 raised to the power of 1/4, which means


\sqrt[4]{81} = \sqrt[4]{3^4} = (3^4)^{\frac{1}{4}}


Now, use the property of exponents (a^b)^c = a^{bc} to convert the expression into


(3^4)^{\frac{1}{4}}  = 3^{4\cdot \frac{1}{4}} = 3^1 = 3

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the equation that we can solve using the given system of equations is:

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<h3>Which equation can be solved using the given system of equations?</h3>

Here we have the system of equations:

y = 3x^5 - 5x^3 + 2x^2 - 10x + 4

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Notice that both x and y should represent the same thing in both equations, then we could write:

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If we remove the middle part, we get:

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Now, this is an equation that only depends on x.

We can simplify it to get:

3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0

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