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nekit [7.7K]
3 years ago
9

Which of the following is NOT a requirement for Hardy-Weinberg equilibrium?

Biology
1 answer:
aev [14]3 years ago
6 0

Answer:

D. Small population size

Explanation:

Hardy-Weinberg equilibrium requires the presence of a large randomly mating population. Small population size makes the population more likely to deviate from the Hardy-Weinberg equilibrium due to sampling error or chance events occurring during the genetic drift. Large population size ensures that the population maintains the constant allele frequencies over generations, that is the Hardy-Weinberg equilibrium.

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Blue flower is dominant to yellow flower. Tall plant is dominant to short. Cross BbTt * BbTt. What precenetage of the offsprings
shtirl [24]

Answer:

The correct answer would be - 25%.

Explanation:

It is given that the Blue flower is dominant over the yellow flower which means Blue is represented by allele B here and allele b for yellow and Bb is a heterozygous case with a blue phenotypic character. Similarly, the Tall plant is dominant over short and represented by T and t respectively.

BbTt is a heterozygous condition and a cross with itself will produce :

Gametes: BT Bt bT and bt

          BT       Bt       bT       bt

BT     BBTT   BBTt   BbTT   BbTt

Bt      BBTt    BBtt    BbTt   Bbtt

bT     BbTT   BbTt    bbTT   bbTt

bt      BbTt     Bbtt    bbTt     bbtt

Here 4 out of 16 offspring are heterozygous for both traits represented by bold alphabets. Therefore the correct answer is 25%

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