Given:
∠PRS and ∠VUW are supplementary.
To prove:
Line TV || Line QS
Solution:
Step 1: Given
∠PRS and ∠VUW are supplementary.
Step 2: By the definition of supplementary angles
Step 3: Angles forming a linear pair sum to 180°
Step 4: By transitive property of equality
step 2 = step 3
Step 5: By algebra cancel the common terms in both side.
Step 6: By converse of corresponding angles postulate
Line TV || Line QS
Hence proved.
X = nr. hrs working for a farmer;
y = nr. hrs. babysitting;
x + y <= 25;
10x + 5y >= 150
a) Solve the system => one of the solution is x =5; y = 20(babysitting)
b) 10 + 12 =22 <= 25; 10*10 + 5*12 = 160 >=150.
Remember, you can do anything to an equation as long as you do it to both sides
and when multiply or divide by a negative in inequalities, flip the direction of the sign
12x-39<9
add 39 to both sides
12x<48
divde bothh sides by 12
x<4
-4x+3<-6
minus 3 both sides
-4x<-9
times both sides by -1 and flip sign
4x>9
divide both sides by 4
x>9/4
Answer:
68% of an investment earning a return between 6 percent and 24 percent.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 15
Standard deviation = 9
How likely is it to earn a return between 6 percent and 24 percent?
6 = 15 - 1*9
6 is one standard deviation below the mean
24 = 15 + 1*9
24 is one standard deviation above the mean
By the empirical rule, there is a 68% of an investment earning a return between 6 percent and 24 percent.
the correct question is
<span>The length of a rectangle is represented by 4a + 3b, and its width is represented by 3a-2b. Write a polynomial for the perimeter of the rectangle. What is the minimum perimeter of the rectangle if a=12 and b is a non-zero </span>whole number?
we know that
Perimeter of a rectangle=2*[length + width]
length=(4a+3b)
width=3a-2b
so
P=2*[(4a+3b)+(3a-2b)]-----> P=2*[7a+b]-----> P=14a+2b
the answer part a) is
A polynomial for the perimeter of the rectangle is P=14a+2b
Part b)
for a=12
P=14*12+2b---------> P=168+2b
<span>the minimum perimeter of the rectangle is for b=1
</span>so
P=168+2*1-----> P=170 units
the answer part b) is
the minimum perimeter of the rectangle is 170 units
