RrXtXt×RrXTY is representing the cross between the white eyed female and red eyed male.
Option D
<h3><u>Explanation:</u></h3>
The genes that are discussed here both are completely dominant over their recessive alleles. In the autosome, the dominant R gene is responsible for red eye and recessive r gene is responsible for sepia eye. But in allosome, the dominant T gene allows the eye colour to be expressed and the recessive t gene doesn't allow eye colour to be expressed and makes it white.
As the female do have 2 X chromosomes and the female is white eyed, then both the chromosomes of female have t gene.
As the male is red eyed and have one X chromosome, so the male must have atleast one R gene in autosome to make the eye colour red and must have T gene in his X chromosome to make it appear in phenotype.
So the most possible cross that is given here is RrXtXt×RrXTY.
Answer: none of the above
Explanation:
None of the above
Answer:
The genotypes of the rooster and the chicken are homozygous and that of their offspring is heterozygous.
This case is called codominance, where the offspring receives an allele from each parent, from the rooster and the hen, because there is codominance, so neither allele is recessive and the phenotype of both alleles is expressed so the phenotype of the offspring is checkered.
We can say then that the chicken and the rooster have equal strength between their alleles. in the cases of codominance the laws of mendel do not apply.
Answer:One EcoRI site can be found in 4096 bp.As EcoRI can not cut a sequence if it is not complete, so 732421 recognition sites in human genome can be found. As you know human genome is linear genome, and when you digest it with Restriction Endonuclease having one recognition site, it always gives two fragments.
Explanation: (Idek how to explain it tbh..sorry :C )
Answer:
the correct answer is option ( B )
