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Andre45 [30]
3 years ago
14

WILL FAN AND MEDAL The table below shows the size of nine families selected at random from two neighborhoods in a large city: Fa

mily Size (in number of people) Neighborhood Q 2 5 4 3 2 5 3 6 5 Neighborhood S 2 3 2 3 7 2 3 3 2 Which neighborhood appears to have a bigger family size? Explain your answer using two or three sentences. Make sure to use facts to support your answer.
Mathematics
1 answer:
Maru [420]3 years ago
3 0
We can compare the two data by their mean

Neighbourhood Q = \frac{2+5+4+3+2+5+3+6+5}{9}= \frac{35}{9}=3.9
Neighbourhood S = \frac{2+3+2+3+7+2+3+3+2}{9}= \frac{27}{9}=3

Neighbourhood Q has larger mean than Neighbourhood S so it appears Neighbourhood Q has larger family size.
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AleksandrR [38]
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6 0
3 years ago
Which statement is true?
valentinak56 [21]

Answer:

  |-3| = 3 and -|-4| = -4

Step-by-step explanation:

The absolute value function changes the sign to positive, if it isn't already. The usual rules of arithmetic and logic apply to these statements.

|-3| = 3 (true) and -|-4| = -4 (true)   ⇒ this statement is true

|-3| = 3 (true) and |-4| = -4 (false)   ⇒ this statement is false

-|3| = 3 (false) and |4| = 4 (true)   ⇒ this statement is false

|-3| = 3 (true) and -|4| = 4 (false)   ⇒ this statement is false

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<em>Additional comment</em>

A compound "and" statement is only true if <u>all</u> of the parts of it are true.

8 0
2 years ago
A ball with a rebound percentage of 45% was dropped from a height of 215feet. What is the height of the ball after the 5th bounc
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Answer:

a

Step-by-step explanation:

8 0
3 years ago
An experienced carpenter can frame a house twice as fast as an apprentice. Working together, it takes the carpenters 2 days. How
AleksAgata [21]

Answer:

<em>6 days</em>

<em></em>

Step-by-step explanation:

Let the time taken by Carpenter working alone = C days

Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2C days

Time taken working together = 2 days

Work done in one day working together = \frac{1}{2}

Work done in one day by Carpenter working alone = \frac{1}{C}

Work done in one day by apprentice working alone = \frac{1}{2C}

Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone =  \frac{1}{C}+\frac{1}{2C} = Work done in one day working together = \frac{1}{2}

\dfrac{1}{C}+\dfrac{1}{2C}=\dfrac{1}{2}\\\Rightarrow \dfrac{2+1}{2C}=\dfrac{1}{2}\\\Rightarrow C = 3\ days

Time taken by Carpenter alone to complete the work = 3 days

Time taken by Apprentice alone to complete the work = 3 \times 2= <em>6 days</em>

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3 years ago
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lana66690 [7]

Answer:

x^2 + y^2 = 49

Step-by-step explanation:

For center (h,k) and radius r, eqution of the respective circle is

(x-h)^2 + (y-k)^2 = r^2

7 0
4 years ago
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