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Andre45 [30]
3 years ago
14

WILL FAN AND MEDAL The table below shows the size of nine families selected at random from two neighborhoods in a large city: Fa

mily Size (in number of people) Neighborhood Q 2 5 4 3 2 5 3 6 5 Neighborhood S 2 3 2 3 7 2 3 3 2 Which neighborhood appears to have a bigger family size? Explain your answer using two or three sentences. Make sure to use facts to support your answer.
Mathematics
1 answer:
Maru [420]3 years ago
3 0
We can compare the two data by their mean

Neighbourhood Q = \frac{2+5+4+3+2+5+3+6+5}{9}= \frac{35}{9}=3.9
Neighbourhood S = \frac{2+3+2+3+7+2+3+3+2}{9}= \frac{27}{9}=3

Neighbourhood Q has larger mean than Neighbourhood S so it appears Neighbourhood Q has larger family size.
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kogti [31]

Answer:

7

Step-by-step explanation:

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Find the circumference and area of a circle with the diameter AB,<br> A(-8,4) and B(4,-1)
bezimeni [28]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-8}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[4-(-8)]^2+[-1-4]^2}\implies AB=\sqrt{(4+8)^2+(-1-4)^2} \\\\\\ AB=\sqrt{144+25}\implies AB=\sqrt{169}\implies \stackrel{\textit{diameter}}{AB=13}~\hfill \boxed{\stackrel{\textit{radius}}{6.5}} \\\\[-0.35em] ~\dotfill

\bf \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad C=2\pi (6.5)\implies C=13\pi \implies C\approx 40.84 \\\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad A=\pi (6.5)^2\implies A=42.25\pi \implies A\approx 132.73

5 0
3 years ago
van budgets 12 a day for groceries for weekdays and 15 a day for weekends. write an expression in simplest form to show his groc
Ksenya-84 [330]
The budget of Van for groceries for 1 week is:

12 $ (per a weekday) * 5 (weekdays) + 15 $(per a weekend day) *2 (weekend days) = 60$ +30$ = 90$

The budget of Van for w weeks is:

90 $ (per week) * w (weeks) = 90w dollars.


Answer: 90w $
6 0
3 years ago
BRAINLIEST <br> Please answer these
zheka24 [161]

3.14 is used for pi.

6.  r = \sqrt{\frac{A}{\pi } }

14.00

7. d = \frac{c}{\pi }

5.00

8. d = 2 \sqrt{\frac{A}{\pi } }

23.01

9. r = \frac{c}{2\pi }

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10. d\pi = 2 \sqrt{{A}

31\pi

11. r\pi = \frac{c}{2}

22.5\pi

Hope this helps :)

6 0
3 years ago
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